题目内容
计算:(1)
| 2 |
| 5 |
| 3 |
| 5 |
(2)(-
| 1 |
| 3 |
| 2 |
| 3 |
(3)(-
| 1 |
| 3 |
| 2 |
| 5 |
(4)(-
| 5 |
| 6 |
| 3 |
| 8 |
(5)
| 1 |
| 2 |
| 2 |
| 3 |
(6)(-
| 1 |
| 2 |
| 1 |
| 3 |
(7)(-1
| 1 |
| 3 |
| 1 |
| 6 |
(8)3
| 1 |
| 4 |
| 1 |
| 12 |
分析:根据有理数加法法则:1.同号两数相加,取相同的符号并把绝对值相加.2.异号两数相加,取绝对值较大的加数的符号,并用较大的绝对值减去较小的绝对值.互为相反数的两个数相加得零.
解答:解:(1)原式=
-
=-
;
(2)原式=-
-
=-1;
(3)原式=-
+
=
;
(4)原式=-
-
=-
;
(5)原式=
-
=
-
=-2
;
(6)原式=-
-
=-
-
=-1
;
(7)原式=-
-
=-
-
=-
=-3
;
(8)原式=
-
=
-
=
=2
.
| 2 |
| 5 |
| 3 |
| 5 |
| 1 |
| 5 |
(2)原式=-
| 1 |
| 3 |
| 2 |
| 3 |
(3)原式=-
| 5 |
| 15 |
| 6 |
| 15 |
| 1 |
| 15 |
(4)原式=-
| 20 |
| 24 |
| 9 |
| 24 |
| 29 |
| 24 |
(5)原式=
| 1 |
| 2 |
| 8 |
| 3 |
| 3 |
| 6 |
| 16 |
| 6 |
| 1 |
| 6 |
(6)原式=-
| 1 |
| 2 |
| 4 |
| 3 |
| 3 |
| 6 |
| 8 |
| 6 |
| 5 |
| 6 |
(7)原式=-
| 4 |
| 3 |
| 13 |
| 6 |
| 8 |
| 6 |
| 13 |
| 6 |
| 21 |
| 6 |
| 1 |
| 2 |
(8)原式=
| 13 |
| 4 |
| 13 |
| 12 |
| 39 |
| 12 |
| 13 |
| 12 |
| 13 |
| 6 |
| 1 |
| 6 |
点评:本题考查了有理数的加法,牢记有理数的加法法则是解题的关键.
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