ÌâÄ¿ÄÚÈÝ
5£®£¨1£©ÏõËáï§µÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª80£®
£¨2£©ÏõËáï§ÖеªÔªËصÄÖÊÁ¿·ÖÊýΪ35%£®
£¨3£©²»ºÏÀíʹÓû¯·Ê»á´øÀ´µÄ»·¾³ÎÊÌâÊÇÍÁÈÀÎÛȾ¡¢Ë®ÓòÎÛȾ¡¢ÍÁÈÀÍË»¯£®¶Ô´ËÄãµÄ½¨ÒéÊǾ¡Á¿Ê¹ÓÃÅ©¼Ò·Ê£®
£¨4£©Å©ÃñÓÃÏõËá笠ø¸ûµØµÄÓñÃ×Ê©¼ÓµªÔªËØ£¬¸ÕºÃÐèÒª160KgÏõËáï§£¬Èô¸ÄÓÃÄòËØ[CO£¨NH2£©2]´ïµ½ÏàͬµÄ·ÊЧ£¬ÔòÐèÒªÄòËØµÄÖÊÁ¿ÊǶàÉÙ£¿
£¨5£©Ä³Å©ÒµÕ¾ÌṩµÄÏõËáï§»¯·Ê£¨²»´¿£©±êÇ©ÈçͼËùʾ£¬Çë¼ÆËã¸Ã»¯·ÊÖÐÏõËá淋Ĵ¿¶È£®
·ÖÎö £¨1£©¸ù¾ÝÏõËá淋Ļ¯Ñ§Ê½¿ÉÖª£¬ÏõËáï§µÄÏà¶Ô·Ö×ÓÖÊÁ¿=£¨µªµÄÏà¶ÔÔ×ÓÖÊÁ¿¡ÁµªÔ×Ó¸öÊý£©+£¨ÇâµÄÏà¶ÔÔ×ÓÖÊÁ¿¡ÁÇâÔ×Ó¸öÊý£©+£¨ÑõµÄÏà¶ÔÔ×ÓÖÊÁ¿¡ÁÑõÔ×Ó¸öÊý£©½øÐзÖÎö£»
£¨2£©¸ù¾ÝÏõËáï§ÖÐNÔªËØµÄÖÊÁ¿·ÖÊýΪ£º$\frac{µªµÄÏà¶ÔÔ×ÓÖÊÁ¿¡ÁµªÔ×Ó¸öÊý}{ÏõËáï§µÄÏà¶Ô·Ö×ÓÖÊÁ¿}$¡Á100%½øÐзÖÎö£»
£¨3£©¸ù¾Ý²»ºÏÀíʹÓû¯·Ê»áÔì³ÉÍÁÈÀÎÛȾ£®Ë®ÎÛȾµÈ½øÐзÖÎö£»
£¨4£©¸ù¾ÝÁ½ÖÖ»¯·ÊÖеªÔªËØÖÊÁ¿ÏàµÈ½øÐзÖÎö£»
£¨5£©¸ù¾ÝÏõËáï§ÖеªÔªËصÄÖÊÁ¿·ÖÊý£¬½áºÏ»¯·ÊÖе嬵ªÁ¿½øÐмÆË㣮
½â´ð ½â£º£¨1£©¸ù¾ÝÏõËá淋Ļ¯Ñ§Ê½¿ÉÖª£¬ÏõËáï§µÄÏà¶Ô·Ö×ÓÖÊÁ¿=14¡Á2+4+16¡Á3=80£»
£¨2£©ÏõËáï§ÖÐNÔªËØµÄÖÊÁ¿·ÖÊýΪ£º$\frac{14¡Á2}{80}$¡Á100%=35%£»
£¨3£©²»ºÏÀíʹÓû¯·Ê»á´øÀ´µÄ»·¾³ÎÊÌâÊÇÍÁÈÀÎÛȾ¡¢Ë®ÓòÎÛȾ¡¢ÍÁÈÀÍË»¯£¬¶Ô´ËÎҵĽ¨ÒéÊǾ¡Á¿Ê¹ÓÃÅ©¼Ò·Ê£»
£¨4£©ÄòËØÖеĵªÔªËØÖÊÁ¿·ÖÊýΪ£º$\frac{28}{60}¡Á100%$£¬ËùÒÔÐèÒªÄòËØµÄÖÊÁ¿Îª£º$\frac{160Kg¡Á35%}{\frac{28}{60}}$=120Kg£»
£¨5£©¼ÙÉèÈ¡1Kg»¯·ÊÉè´¿¶ÈΪx£¬ËùÒÔ1Kg¡Á28%=1Kg¡Áx¡Á35%£¬ËùÒԸû¯·ÊÖÐÏõËá淋Ĵ¿¶ÈΪ£ºx=$\frac{28%}{35%}$¡Á100%=80%£®
¹Ê´ð°¸Îª£º£¨1£©80£»
£¨2£©35%£»
£¨3£©ÍÁÈÀÎÛȾ¡¢Ë®ÓòÎÛȾ¡¢ÍÁÈÀÍË»¯£¬¾¡Á¿Ê¹ÓÃÅ©¼Ò·Ê£»
£¨4£©120Kg£»
£¨5£©80%£®
µãÆÀ ±¾ÌâÄѶȲ»´ó£¬¿¼²éͬѧÃÇÁé»îÔËÓû¯Ñ§Ê½µÄÓйؼÆËã½øÐзÖÎöÎÊÌâ¡¢½â¾öÎÊÌâµÄÄÜÁ¦£®
| A£® | ÈÜÒºÖÐÈÜÖÊ¿ÉÒÔÊǹÌÌå»òÆøÌå | |
| B£® | θËá¹ý¶àµÄ²¡ÈËÔÚ¿Õ¸¹Ê±×îºÃ¶àºÈһЩÄûÃÊÖ | |
| C£® | º¬Ì¼ÔªËصϝºÏÎïÒ»¶¨ÊÇÓлúÎï | |
| D£® | Óò»Ðâ¸ÖÖÆ×÷µÄÆ÷¾ßÓÀÔ¶²»»áÉúÐâ |
| A£® | úµÄÆø»¯ÊÇÖ¸½«¹Ì̬ú·ÛËé³ÉÆøÌ¬Ãº£¬ÒÔʹúȼÉÕʱÄÜÓëÑõÆø³ä·Ö½Ó´¥¶øÍêȫȼÉÕ | |
| B£® | úµÄ½¹»¯ÊÇʹúÔÚ¸ô¾ø¿ÕÆøµÄÇé¿öϼÓÇ¿ÈÈʹú·Ö½â£¬Òò´Ë¸Ã±ä»¯ÊÇ»¯Ñ§±ä»¯ | |
| C£® | ÔÚÆûÓÍÖмÓÈëÒ»¶¨±ÈÀýµÄÒÒ´¼£¨Ë׳ƣº¾Æ¾«£©£¬Ê¹È¼ÁÏȼÉÕ¸ü³ä·Ö£¬¿É¼õÉÙ»·¾³ÎÛȾ | |
| D£® | ú¡¢Ê¯ÓÍ¡¢ÌìÈ»ÆøÊÇÂñ²ØÔÚµØÏµIJ»¿ÉÔÙÉúµÄ»¯Ê¯È¼ÁÏ£¬Òª½ÚÔ¼ÀûÓà |
| A£® | ÇâÆøºÍÒºÇâ¶¼¿ÉÒÔ×öȼÁÏ--ÏàͬÎïÖʵķÖ×Ó£¬»¯Ñ§ÐÔÖÊÏàͬ | |
| B£® | Óþ¯È®ËѾȵØÕðÖб»ÂñÈËÔ±--·Ö×ÓÔÚ²»¶ÏÔ˶¯ | |
| C£® | ÓÃË®ÒøÎ¶ȼƲâÁ¿ÌåÎÂ--ζÈÉý¸ß£¬Ô×Ó¼ä¸ô±ä´ó | |
| D£® | Ë®ÉÕ¿ªºó°Ñºø¸Ç³åÆð--ζÈÉý¸ß£¬·Ö×Ó±ä´ó |
£¨1£©Ð´³öÒÇÆ÷a¡¢bµÄÃû³Æ£ºa³¤¾±Â©¶·£»b×¶ÐÎÆ¿£®
£¨2£©Ð´³öAͼÖвúÉúÆøÌåµÄ»¯Ñ§±í´ïʽCaCO3+2HCl=CaCl2+H2O+CO2¡ü£®¼ìÑé¶þÑõ»¯Ì¼ÊÇ·ñÊÕ¼¯ÂúµÄ·½·¨Êǽ«Ò»¸ùȼ×ŵÄľÌõƽ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬Ä¾ÌõϨÃð£¬Ö¤Ã÷ÂúÁË£®
£¨3£©BͼÖУ¬°Ñ¶þÑõ»¯Ì¼ÆøÌåÂýÂýµ¹Èë·ÅÓÐȼ×ŵÄÀ¯ÖòµÄÉÕ±ÖУ¬Ï²ãÀ¯ÖòÏÈÃð£¬ËµÃ÷¶þÑõ»¯Ì¼¾ßÓв»ÄÜȼÉÕ¡¢²»Ö§³ÖȼÉÕºÍÃÜ¶È±È¿ÕÆø´óÐÔÖÊ£®ÕâÒ»ÐÔÖÊÔÚʵ¼ÊÉú»îÖеÄÓ¦ÓÃΪÃð»ð£®
£¨4£©CͼÖÐÂÝÐý×´ÌúË¿µÄÄ©¶Ëϵһ¸ù»ð²ñµÄ×÷ÓÃÊÇÒýȼÌúË¿£®
£¨5£©Ð¡Ã÷°´CͼʵÑéʱ£¬¼¯ÆøÆ¿Õ¨ÁÑÁË£¬Æä¿ÉÄܵÄÔÒòÊÇȼ×ŵÄÌúË¿Åöµ½¼¯ÆøÆ¿±ÚµÈ£®
£¨6£©Ð¡Ã÷¶ÔÌúË¿ÔÚÑõÆøÖÐȼÉÕΪʲô»á»ðÐÇËÄÉä½øÐÐ̽¾¿£®Ï±íÊÇËû½«´¿Ã¾ÌõºÍ²»Í¬º¬Ì¼Á¿µÄÌúË¿£¨Ã¾ÌõºÍÌúË¿ÆðÂë¾ùΪ0.4mm£©·ÅÈëÑõÆøÖÐȼÉÕʱµÄʵÑéÏÖÏóµÄ¼Ç¼£®
| ÎïÖÊ | þÌõ | º¬Ì¼0.05%µÄÌúË¿ | º¬Ì¼0.2%µÄÌúË¿ | º¬Ì¼0.6%µÄÌúË¿ |
| ȼÉÕʱ µÄÏÖÏó | ¾çÁÒȼÉÕ£¬·¢³ö Ò«Ñ۰׹⣬ÎÞ»ðÐÇ | ¾çÁÒȼÉÕ ¼«ÉÙ»ðÐÇ | ¾çÁÒȼÉÕ ÉÙÁ¿»ðÐÇ | ¾çÁÒȼÉÕ »ðÐÇËÄÉä |
ÌúË¿ÔÚÑõÆøÖÐȼÉÕ²úÉú»ðÐÇËÄÉäµÄÏÖÏóÊÇÓÉÓÚÌúË¿Öк¬ÓеÄ̼ÒýÆðµÄ£®
| A£® | ÌúË¿ÔÚÑõÆøÖоçÁÒȼÉÕ£¬»ðÐÇËÄÉ䣬·Å³öÈÈÁ¿£¬Éú³ÉºÚÉ«¹ÌÌå | |
| B£® | ÁòÔÚ¿ÕÆøÖÐȼÉÕ·¢³ö΢ÈõµÄµÀ¶É«»ðÑæ£¬·Å³ö´óÁ¿µÄÈÈ£¬Éú³É¶þÑõ»¯Áò | |
| C£® | Á×ÔÚ¿ÕÆøÖÐȼÉշųö´óÁ¿µÄÈÈ£¬Éú³É´óÁ¿µÄÑÌÎí | |
| D£® | ÂÁË¿²åÈëµ½ÁòËáÍÈÜÒº£¬ÓкìÉ«¹ÌÌåÎö³ö£¬ÈÜÒºÖð½¥ÓÉÀ¶É«±äΪdzÂÌÉ« |