ÌâÄ¿ÄÚÈÝ

5£®ÈçͼÊÇijͬѧÅäÖÆ50gÖÊÁ¿·ÖÊýΪ15%µÄÕáÌÇÈÜÒºµÄ²Ù×÷¹ý³ÌʾÒâͼ£®ÊԻشð£º

£¨1£©ÅäÖÆÈÜÒºµÄ²Ù×÷²½ÖèÓУº¢ÙÈܽ⣻¢Ú³ÆÁ¿£»¢Û¼ÆË㣻¢Ü×°Æ¿´æ·Å£®ÔòÕýÈ·µÄ²Ù×÷˳ÐòÊǢۢڢ٢ܣ¨ÌîÐòºÅ¢Ù¡«¢Ü£©£®
£¨2£©ÇëÖ¸³öʵÑé¹ý³ÌÖдíÎóµÄ²Ù×÷²½ÖèÐòºÅAB£¬¾ÀÕý´íÎóºó³ÆµÃÕáÌǵÄÖÊÁ¿ÊÇ7.5g£®
£¨3£©E²Ù×÷Öв£Á§°ôµÄ×÷ÓÃÊǽÁ°è£¬¼Ó¿ìÂÈ»¯ÄƵÄÈܽâËÙÂÊ£®
£¨4£©Èç¹ûÅäÖÆÕáÌÇÈÜÒº¹ý³ÌÖУ¬ÈܽâʱÓÐÉÙÁ¿Ë®½¦³ö£¬ÔòÈÜÒºÈÜÖʵÄÖÊÁ¿·ÖÊý½«´óÓÚ£¨Ìî¡°´óÓÚ£¬µÈÓÚ»òСÓÚ£©15%£®

·ÖÎö £¨1£©¸ù¾ÝÅäÖÆÈÜÖÊÖÊÁ¿·ÖÊýÒ»¶¨µÄÈÜÒºµÄ»ù±¾²½Ö裬½øÐзÖÎö½â´ð£®
£¨2£©¸ù¾ÝÍÐÅÌÌìÆ½µÄʹÓÃÒª×ñÑ­¡°×óÎïÓÒÂ롱µÄÔ­Ôò¡¢Á¿Í²¶ÁÊýʱÊÓÏßÒªÓë°¼ÒºÃæµÄ×îµÍ´¦±£³Öˮƽ£¬ÈÜÖÊÖÊÁ¿=ÈÜÒºÖÊÁ¿¡ÁÈÜÖʵÄÖÊÁ¿·ÖÊý£¬½øÐзÖÎö½â´ð£®
£¨3£©E²Ù×÷ΪÈܽâ²Ù×÷£¬½áºÏ²£Á§°ôµÄ×÷ÓýøÐзÖÎö½â´ð£®
£¨4£©Èç¹ûÅäÖÆÕáÌÇÈÜÒº¹ý³ÌÖУ¬ÈܽâʱÓÐÉÙÁ¿Ë®½¦³ö£¬»áÔì³Éʵ¼ÊÁ¿È¡µÄË®µÄÌå»ýƫС£¬½øÐзÖÎö½â´ð£®

½â´ð ½â£º£¨1£©ÅäÖÆ50gÖÊÁ¿·ÖÊýΪ15%µÄÕáÌÇÈÜÒº£¬Ê×ÏȼÆËãÅäÖÆÈÜÒºËùÐèÕáÌǺÍË®µÄÖÊÁ¿£¬ÔÙ³ÆÁ¿ËùÐèµÄÕáÌǺÍÁ¿È¡Ë®£¬×îºó½øÐÐÈܽ⣬ÔòÕýÈ·µÄ²Ù×÷˳ÐòÊǢۢڢ٢ܣ®
£¨2£©ÍÐÅÌÌìÆ½µÄʹÓÃÒª×ñÑ­¡°×óÎïÓÒÂ롱µÄÔ­Ôò£¬Í¼ÖÐËùʾ²Ù×÷íÀÂëÓëҩƷλÖ÷ŷ´ÁË£»Á¿È¡ÒºÌåʱ£¬ÊÓÏßÓëÒºÌåµÄ°¼ÒºÃæ×îµÍ´¦±£³Öˮƽ£¬Í¼ÖÐÑöÊӿ̶ȣ®
ÈÜÖÊÖÊÁ¿=ÈÜÒºÖÊÁ¿¡ÁÈÜÖʵÄÖÊÁ¿·ÖÊý£¬ÅäÖÆ50gÖÊÁ¿·ÖÊýΪ15%µÄÕáÌÇÈÜÒº£¬ÐèÂÈ»¯ÄƵÄÖÊÁ¿=50g¡Á15%=7.5g£®
£¨3£©E²Ù×÷ΪÈܽâ²Ù×÷£¬²£Á§°ôµÄ×÷ÓÃÊǽÁ°è£¬¼Ó¿ìÈܽâËÙÂÊ£®
£¨4£©Èç¹ûÅäÖÆÕáÌÇÈÜÒº¹ý³ÌÖУ¬ÈܽâʱÓÐÉÙÁ¿Ë®½¦³ö£¬»áÔì³Éʵ¼ÊÁ¿È¡µÄË®µÄÌå»ýƫС£¬ÔòʹÈÜÖÊÖÊÁ¿·ÖÊýÆ«´ó£®
¹Ê´ð°¸Îª£º£¨1£©¢Û¢Ú¢Ù¢Ü£»£¨2£©AB£»7.5£»£¨3£©½Á°è£¬¼Ó¿ìÈܽâËÙÂÊ£»£¨4£©´óÓÚ£®

µãÆÀ ±¾ÌâÄѶȲ»´ó£¬Ã÷È·ÅäÖÆÒ»¶¨ÈÜÖÊÖÊÁ¿·ÖÊýµÄÈÜҺʵÑé²½Ö裨¼ÆËã¡¢³ÆÁ¿¡¢Èܽ⣩¡¢×¢ÒâÊÂÏîµÈÊÇÕýÈ·½â´ð±¾ÌâµÄ¹Ø¼ü£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
5£®£¨1£©Èçͼ1ËùʾµÄÒÇÆ÷ºÍ×°Ö㬿ÉÓÃʵÑéÊÒÖÆÈ¡Ä³Ð©ÆøÌ壮
¢ÙÓøßÃÌËá¼ØÖÆÈ¡ÑõÆøµÄ·¢Éú×°ÖÿÉÑ¡ÔñÈçͼÖеÄABCE£¨Ìî±êºÅ£©½øÐÐ×éºÏ£®
¢ÚʵÑéÊÒÖÆÈ¡¶þÑõ»¯Ì¼µÄ»¯Ñ§·½³ÌʽΪCaCO3+2HCl¨TCaCl2+H2O+CO2¡ü£®ÓÃFÊÕ¼¯¶þÑõ»¯Ì¼Ê±£¬Í¨Èë¶þÑõ»¯Ì¼Ò»¶Îʱ¼äºó£¬½ÓÏÂÀ´µÄ²Ù×÷ÊǰÑȼÉÕµÄľÌõ·ÅÔÚ¼¯ÆøÆ¿¿Ú£¬Ä¾ÌõϨÃð£¬ÒƳöµ¼Æø¹Ü£¬¸ÇÉϲ£Á§Æ¬£®
£¨2£©»¯Ñ§ÐËȤС×éÔÚÀÏʦµÄÖ¸µ¼Ï£¬¶Ô´¿¼î£¨Na2CO3£©ÈÜÒºµÄËá¼îÐÔ½øÐÐÒÔÏÂ̽¾¿£®
̽¾¿1£ºNa2CO3ÈÜÒºËá¼îÐÔ¼ìÑé
¢ÙÇëÄ㽫ʵÑ鱨¸æÌîдÍê³É£®
 ÊµÑé²½Öè ÊµÑéÏÖÏó ÊµÑé½áÂÛ
 È¡ÉÙÁ¿Na2CO3ÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈëÉÙÁ¿µÄ
·Ó̪ÊÔÒº 
 
·Ó̪ÊÔÒº±äºìÉ«
Na2CO3Ë®ÈÜÒº³Ê¼îÐÔ
̽¾¿2£ºÓ°ÏìNa2CO3ÈÜÒºËá¼î¶ÈµÄÒòËØÑо¿
²»Í¬Î¶ÈÏ£¨20¡æºÍ30¡æ£©£¬ÓÃpH¼Æ·Ö±ð²â¶¨²»Í¬ÈÜÖÊÖÊÁ¿·ÖÊýµÄNa2CO3ÈÜÒº£¨1%ºÍ5%£©µÄpHÖµ£¬»ñµÃµÄÏà¹ØÊµÑéÊý¾ÝÈçϱíËùʾ£®
 ÊµÑé±àºÅ Na2CO3ÈÜÒºµÄÈÜÖÊÖÊÁ¿·ÖÊý£¨¾ùÈ¡2mL£© ÊµÑéζȠpH
 a 1% 20¡æ 11.6
 b 1% 30¡æ 11.8
 c 5% 20¡æ 12.1
 d 5% 30¡æ12.4
¢ÚÒª»ñÈ¡Na2CO3ÈÜÒºÈÜÖÊÖÊÁ¿·ÖÊý¶ÔÆä¼îÐÔÇ¿ÈõÓ°ÏìµÄ½áÂÛ£¬¿É±È½ÏµÄʵÑé±àºÅÊÇac»òbd£¨Ð´Ò»ÖÖ×éºÏ£©£®
¢Û´ÓÉÏÊöʵÑéÊý¾ÝÖеóöζȶÔNa2CO3ÈÜÒº¼îÐÔÇ¿ÈõÓ°ÏìµÄ½áÂÛÊÇ̼ËáÄÆÈÜÒºÖÊÁ¿·ÖÊýÒ»¶¨Ê±£¬Î¶ÈÔ½¸ß£¬¼îÐÔԽǿ£®
̽¾¿3£ºNa2CO3ÈÜÒºËá¼îÐÔÔ­ÒòµÄ³õ²½Ì½Îö
È¡2mL5%µÄNa2CO3ÈÜÒºÓÚÊÔ¹ÜÖУ¬ÖðµÎ¼ÓÈëÏ¡ÑÎËᣬ²¢²â¶¨¸ÃʵÑé¹ý³ÌÈÜÒºµÄpH±ä»¯Çé¿ö£¬»ñµÃÊý¾ÝÈçͼËùʾ£®
¢Ü·ÖÎöͼ2ÖÐa¡¢b¡¢cÈý´¦ÈÜÒºËùº¬ÈÜÖʵIJ»Í¬£¬´Ó¹¹³ÉÎïÖÊ΢Á£µÄÊÓ½ÇÍÆ¶Ï£ºNa2CO3ÈÜÒº³Ê¼îÐÔÓëNa2CO3ÖеÄCO32-£¨ÌîÀë×Ó·ûºÅ£©Óйأ®
¢ÝÇëÄãÔÙÉè¼ÆÒ»¸öʵÑéÖ¤Ã÷¢ÜËùµÃµÄ½áÂÛ£ºÊµÑé²½Ö裺ȡÊÊÁ¿Ì¼ËáÄÆÈÜÒºÓÚÊÔ¹ÜÖУ¬¼ÓÈëÊÊÁ¿·Ó̪ÊÔÒº£¬ÔÙ¼ÓÈë×ãÁ¿ÂÈ»¯¸ÆÈÜÒº£»
ʵÑéÏÖÏó£ºÈÜÒº±ä³ÉºìÉ«£¬²úÉú°×É«³Áµí£¬ÈÜÒºÓɺìÉ«±ä³ÉÎÞÉ«£»
ʵÑé½áÂÛ£ºÌ¼ËáÄÆÈÜÒºÏÔ¼îÐÔÓë̼ËáÄÆÖеÄ̼Ëá¸ùÀë×ÓÓйأ¨Ð´³öʵÑé²½ÖèºÍÔ¤ÆÚ¹Û²ìµ½µÄÏÖÏó£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø