ÌâÄ¿ÄÚÈÝ
СÃ÷¹ºµÃÓÃÓÚʳÓþúÖÖÖ²µÄÇáÖÊ̼Ëá¸Æ£¬±êÇ©ÈçÏ¡£Îª²â¶¨Æäº¬¸ÆÁ¿Ð¡Ã÷½øÐеÄʵÑéÊÇ£º
¢Ù³ÆÈ¡ÑùÆ·5g£»
¢Ú¼ÓÈë×ãÁ¿7.3£¥µÄÑÎËá³ä·Ö·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCO3+2HCl==CaCl2+H2O+CO2¡ü
¢Û½«ËùÉú³ÉµÄÈ«²¿ÆøÌå³ýÔÓ¸ÉÔïºó£¬Í¨Èë100gÇâÑõ»¯ÄÆÅ¨ÈÜÒº£¬·´Ó¦ºó´ËÈÜÒº×ÜÖÊÁ¿Îª102.2g¡£
¢Ù³ÆÈ¡ÑùÆ·5g£»
¢Ú¼ÓÈë×ãÁ¿7.3£¥µÄÑÎËá³ä·Ö·´Ó¦£¬·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCaCO3+2HCl==CaCl2+H2O+CO2¡ü
¢Û½«ËùÉú³ÉµÄÈ«²¿ÆøÌå³ýÔÓ¸ÉÔïºó£¬Í¨Èë100gÇâÑõ»¯ÄÆÅ¨ÈÜÒº£¬·´Ó¦ºó´ËÈÜÒº×ÜÖÊÁ¿Îª102.2g¡£
![]()
Çë¼ÆË㣬²¢»Ø´ðÏÂÁÐÓйØÎÊÌ⣺
(1)ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙ?
(2)±êÇ©±êʾµÄº¬¸ÆÁ¿ÊÇ·ñÕýÈ·£¬Èô²»ÕýÈ·Ó¦ÈçºÎ¸ÄÕý?
(1)ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙ?
(2)±êÇ©±êʾµÄº¬¸ÆÁ¿ÊÇ·ñÕýÈ·£¬Èô²»ÕýÈ·Ó¦ÈçºÎ¸ÄÕý?
(1)½â£ºÉèÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿Îªx
CaCO3+2HCl==CaCl2+H2O+CO2¡ü
100¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡44
¡¡x¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡102.2g-100g
100:x£½44:2.2g
x=5g
ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ100£¥
(2)̼Ëá¸ÆÖк¬¸ÆÔªËصÄÖÊÁ¿·ÖÊýΪ
±êÇ©ÖС°º¬¸Æ£¾40£¥¡±Ó¦¸Ã¸ÄΪ¡°º¬¸Æ¡Ü40£¥¡±
´ð£ºÑùÆ·ÖÐ̼Ëá¸ÆµÄº¬Á¿Îª100£¥£¬±êÇ©ÖС°º¬¸Æ£¾40%¡±Ó¦¸Ã¸ÄΪ¡°º¬¸Æ¡Ü40£¥¡±¡£
CaCO3+2HCl==CaCl2+H2O+CO2¡ü
100¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡44
¡¡x¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡¡102.2g-100g
100:x£½44:2.2g
x=5g
ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýΪ100£¥
(2)̼Ëá¸ÆÖк¬¸ÆÔªËصÄÖÊÁ¿·ÖÊýΪ
±êÇ©ÖС°º¬¸Æ£¾40£¥¡±Ó¦¸Ã¸ÄΪ¡°º¬¸Æ¡Ü40£¥¡±
´ð£ºÑùÆ·ÖÐ̼Ëá¸ÆµÄº¬Á¿Îª100£¥£¬±êÇ©ÖС°º¬¸Æ£¾40%¡±Ó¦¸Ã¸ÄΪ¡°º¬¸Æ¡Ü40£¥¡±¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
СÃ÷¹ºµÃÓÃÓÚʳÓþúÖÖÖ²µÄÇáÖÊ̼Ëá¸Æ£¬±êÇ©Èçͼ£®Îª²â¶¨Ì¼Ëá¸ÆµÄÖÊÁ¿·ÖÊýСÃ÷½øÐеÄʵÑ飺
| XXÅÆ ÇáÖÊ̼Ëá¸Æ º¬Á¿£ºº¬¸Æ£¾40% ÖÊÁ¿£º25kg XX»¯¹¤³§³öÆ·¢Ù³ÆÈ¡ÑùÆ·8g·ÅÈëÒ»ÉÕ±ÖУ» ¢ÚÔÙÍùÉÏÊöÉÕ±ÖмÓÈë50gµÄÑÎËᣨ×ãÁ¿£©³ä·Ö·´Ó¦£» ¢Û³ÆÁ¿·´Ó¦ºóÉÕ±ÖÐÊ£ÓàÎïÖʵÄÖÊÁ¿Îª54.7g£® Çë¼ÆË㣬²¢»Ø´ðÏÂÁÐÓйØÎÊÌ⣺ £¨1£©·´Ó¦¹ý³ÌÖвúÉúµÄÆøÌåÖÊÁ¿ÊǶàÉÙ£¿ £¨2£©ÑùÆ·ÖÐ̼Ëá¸ÆµÄÖÊÁ¿·ÖÊýÊǶàÉÙ£¿ £¨3£©ÇëÄãͨ¹ý¼ÆËã»Ø´ð£º±êÇ©±êʾµÄº¬¸ÆÁ¿ÊÇ·ñÕýÈ·£¿ |