ÌâÄ¿ÄÚÈÝ

1£®3ÔÂ22ÈÕÊÇ¡°ÊÀ½çË®ÈÕ¡±£¬Ë®ÓëÈËÀàµÄÉú»îºÍÉú²úÃÜÇÐÏà¹Ø£¬ÈçͼÊÇË®µç½âµÄ¹ý³ÌʾÒâͼ£¬Çë»Ø´ðÏÂÁÐÎÊÌ⣻

£¨1£©ÕôÁóË®ÊôÓÚ´¿¾»ÎÌî´¿¾»Îï»òÕß»ìºÏÎ£¬Ë®µç½â²úÉúÑõÆøºÍÇâÆø£¬ËµÃ÷Ë®ÊÇÓÉÇâÔªËØºÍÑõÔªËØ×é³ÉµÄ£®
£¨2£©¸ù¾ÝÈçͼÖеĻ¯Ñ§±ä»¯¹ý³Ì£¬ÕâÒ»»¯Ñ§±ä»¯ÖеÄ×îСÁ£×ÓÊÇD£¨Ìî±êºÅ£©
A£®Ë®·Ö×Ó   B£®Çâ·Ö×Ó    C£®Ñõ·Ö×Ó    D£®ÇâÔ­×ÓºÍÑõÔ­×Ó
£¨3£©ÏÂÁйØÓÚË®µÄÌìȻѭ»·µÄ˵·¨ÖÐÕýÈ·µÄÊÇD
¢ÙË®ÔÚÌìȻѭ»·¹ý³ÌÖÐʵÏÖÁËË®µÄ×ÔÉí¾»»¯
¢ÚË®µÄÌìȻѭ»·ÊÇͨ¹ýË®µÄÈý̬±ä»¯ÊµÏÖµÄ
¢ÛÌ«ÑôΪˮµÄÌìȻѭ»·ÌṩÁËÄÜÁ¿
¢ÜË®µÄÌìȻѭ»·Íê³ÉÁËË®×ÊÔ´µÄÖØÐ·ÖÅ䣮
A£®¢Ù¢ÛB£®¢Ù¢ÚC£®¢Û¢ÜD£®¢Ù¢Ú¢Û¢Ü

·ÖÎö £¨1£©¸ù¾ÝÕôÁóË®µÄ×é³ÉºÍµç½âË®µÄ½áÂÛ·ÖÎö»Ø´ð£»
£¨2£©¸ù¾ÝË®µÄ±ä»¯µÄÌØÕ÷·ÖÎö»Ø´ð£»
£¨3£©Ë®µÄÌìȻѭ»·Ò»°ã°üÀ¨½µË®¡¢¾¶Á÷¡¢Õô·¢Èý¸ö½×¶Î£®½µË®°üÀ¨Óꡢѩ¡¢Îí¡¢±¢µÈÐÎʽ£»¾¶Á÷ÊÇÖ¸ÑØµØÃæºÍµØÏ¶¯×ŵÄË®Á÷£¬°üÀ¨µØ±í¾¶Á÷ºÍµØÏ¾¶Á÷£»Õô·¢°üÀ¨Ë®ÃæÕô·¢¡¢Ö²ÎïÕôÌÚ¡¢ÍÁÈÀÕô·¢µÈ£®Ë®ÔÚÌìȻѭ»·¹ý³ÌÖÐʵÏÖÁËË®µÄ×ÔÉí¾»»¯£®

½â´ð ½â£º£¨1£©ÕôÁóË®ÊÇÓÐÒ»ÖÖÎïÖÊ×é³ÉµÄ£¬ÊôÓÚ´¿¾»Îˮµç½â²úÉúÑõÆøºÍÇâÆø£¬ËµÃ÷Ë®ÊÇÓÉÇâÔªËØºÍÑõÔªËØ ×é³ÉµÄ£®
£¨2£©ÓÉͼÖÐ΢Á£µÄ±ä»¯¿ÉÖª£¬ÕâÒ»»¯Ñ§±ä»¯ÖеÄ×îСÁ£×ÓÊÇÇâÔ­×ÓºÍÑõÔ­×Ó£»
£¨3£©ÏÂÁйØÓÚË®µÄÌìȻѭ»·µÄ˵·¨ÖУº¢ÙË®ÔÚÌìȻѭ»·¹ý³ÌÖÐʵÏÖÁËË®µÄ×ÔÉí¾»»¯£»¢ÚË®µÄÌìȻѭ»·ÊÇͨ¹ýË®µÄÈý̬±ä»¯ÊµÏֵ컢ÛÌ«ÑôΪˮµÄÌìȻѭ»·ÌṩÁËÄÜÁ¿£»¢ÜË®µÄÌìȻѭ»·Íê³ÉÁËË®×ÊÔ´µÄÖØÐ·ÖÅ䣻¶¼ÕýÈ·£¬ËùÒÔDÕýÈ·£®
¹Ê´ðΪ£º£¨1£©´¿¾»ÎÇâÔªËØ¡¢ÑõÔªËØ£»£¨2£©D£»£¨3£©D£®

µãÆÀ ±¾ÌâÖ÷Òª¿¼²é½âË®µÄʵÑéÏÖÏóºÍ½áÂÛ¡¢Ë®µÄÌìȻѭ»·¡¢Ë®ÔÚÌìȻѭ»·¹ý³ÌÖÐʵÏÖÁËË®µÄ×ÔÉí¾»»¯£¬Ë®µÄÌìȻѭ»·Íê³ÉÁËË®×ÊÔ´µÄÖØÐ·ÖÅ䣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
9£®ÎÒ¹ú»¯¹¤×¨¼ÒºîµÂ°ñÔøÎªÊÀ½çÖÆ¼î¹¤Òµ×÷³öÁËÍ»³ö¹±Ï×£®¡°ºîÊÏÖÆ¼î·¨¡±ÊÇÒÔʳÑΡ¢°±Æø¡¢¶þÑõ»¯Ì¼µÈΪԭÁÏÏÈÖÆµÃNaHCO3£¬½ø¶øÉú²ú³ö´¿¼î£®ÆäÉú²ú¹ý³ÌÓû¯Ñ§·½³Ìʽ¿É¼òÒª±íʾΪ£º
¢ÙNH3+H2O+CO2=NH4HCO3£»¢ÚNH4HCO3+NaCl=NaHCO3¡ý+NH4Cl£»¢Û2NaHCO3$\frac{\underline{\;\;¡÷\;\;}}{\;}$Na2CO3+H2O+CO2¡ü£»
£¨1£©¡°ºîÊÏÖÆ¼î·¨¡±Éú²ú¹ý³ÌÖÐĩɿ¼°µ½µÄ»ù±¾·´Ó¦ÀàÐÍÊÇA£®
A£®Öû»·´Ó¦£»B£®»¯ºÏ·´Ó¦£»C£®·Ö½â·´Ó¦£»D£®¸´·Ö½â·´Ó¦
£¨2£©µÚ¢Ú²½ÖмÓÈëµÄÊÇĥϸµÄʳÑηۣ¬Ê³ÑÎĥϸµÄÄ¿µÄÊǼӿìÂÈ»¯ÄƵÄÈܽâËÙÂÊ£®
ÈôµÚ¢Ú²½Öеõ½µÄNaHCO3Öк¬ÓÐÉÙÁ¿µÄNH4HCO3£¬µ«²»»áÓ°Ïì²úÆ·Na2CO3µÄ´¿¶È£¬Ô­ÒòÊÇNH4HCO3$\frac{\underline{\;\;¡÷\;\;}}{\;}$NH3¡ü+H2O+CO2¡ü£¨Óû¯Ñ§·½³Ìʽ±íʾ£©£®
£¨3£©Èô´¿¼îÖк¬ÓÐNaHCO3ÔÓÖÊ£¬Îª²â¶¨ÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊý£¬ÓÃͼÖеÄ×°ÖýøÐÐʵÑ飮Ö÷ҪʵÑé²½ÖèÈçÏ£º
ÓÃÌìÆ½×¼È·³ÆÁ¿³ö¸ÉÔïÊԹܵÄÖÊÁ¿Îª20.2¿Ë£¬È»ºó³ÆÈ¡4.0¿ËÒÑÑÐËéµÄ´¿¼îÑùÆ·²¢·ÅÈë¸ÉÔïµÄÊÔ¹ÜÖУ®Óþƾ«µÆ¼ÓÈÈ£¬´ý³ä·Ö·´Ó¦²¢ÀäÈ´ºó£¬ÔÚÌìÆ½ÉϳƳöÊԹܺÍ̼ËáÄÆµÄÖÊÁ¿23.5¿Ë£®
¢ÙÍ£Ö¹¼ÓÈÈǰ£¬Òª½øÐеIJÙ×÷Êǰѵ¼¹ÜÒÆ³öÉÕ±­£®
¢Ú¸ÃÊÔÑùÖд¿¼îµÄÖÊÁ¿·ÖÊýΪ52.5%£®
6£®¸ÖÌúµÄÒ±Á¶ÊÇÈËÀàÎÄÃ÷µÄÒ»¸öÖØÒª±êÖ¾£®Í¼1ÊÇʵÑéÊÒÄ£ÄâÁ¶ÌúµÄ×°ÖÃͼ£®

£¨1£©Ð´³öͼ1ÖÐA´¦·¢ÉúµÄ»¯Ñ§·´Ó¦·½³Ìʽ£ºFe2O3+3CO$\frac{\underline{\;¸ßÎÂ\;}}{\;}$2Fe+3CO2£»
£¨2£©ÊµÑé¹ý³ÌÖÐͨÈëCOÖÊÁ¿ÓëºìÉ«·ÛÄ©ÖÊÁ¿µÄ¹ØÏµÈçͼ2Ëùʾ£®¸ù¾Ýͼʾ£¬ÏÂÁÐ˵·¨²»ÕýÈ·µÄÊǢ٢ݣ»£¨ÌîÐòºÅ£©
¢Ùaµã±íʾ¿ªÊ¼Í¨ÈëCO£¬·´Ó¦¿ªÊ¼·¢Éú
¢Úbµã±íʾͨÈëCOÒ»¶Îʱ¼äºó¼ÓÈÈ£¬·´Ó¦¿ªÊ¼·¢Éú
¢Ûcµã±íʾºìÉ«·ÛÄ©Òѳä·Ö²Î¼Ó·´Ó¦
¢Üdµã±íʾ·´Ó¦½áÊøºóÈÔÐè¼ÌÐøÍ¨ÈëCO
¢Ý¿É¸ù¾ÝͨÈëCOµÄÖÊÁ¿¼ÆËã³öºìÉ«·ÛÄ©µÄÖÊÁ¿
£¨3£©Í¼1×°ÖÃÖеIJ»×ãÖ®´¦ÊÇûÓжÔÎ²Æø½øÐд¦Àí£®
£¨4£©¸ÃʵÑéÁ¶ÖƵÄÌúÓ빤ҵÁ¶ÖƳöµÄÌú×î´óµÄÇø±ðÊǸÃʵÑéÁ¶ÖƵÄÌúÊÇ´¿¾»Î¹¤ÒµÁ¶ÖƵÄÉúÌúÊÇ»ìºÏÎº¬ÓÐÒ»¶¨Á¿µÄ̼£®
£¨5£©Ä³»¯Ñ§Ð¡×éµÄͬѧÃÇÀûÓÃÉÏÊöʵÑé¶ÔÒ»·Ý¹ÌÌåÑùÆ·½øÐÐÁË̽¾¿£®Í¨¹ýʵÑéÒÑÈ·¶¨¸ÃÑùÆ·ÓÉÑõ»¯ÌúºÍÌú·Û»ìºÏ¶ø³É£®ËûÃÇÈ¡ÁË7.2g¹ÌÌåÑùÆ·£¬ÓÃͼ1ËùʾµÄ×°ÖÃÖØÐÂʵÑ飬²â¶¨µÄ²¿·ÖÊý¾ÝÈçͼ3Ëùʾ£¬ÔòÔ­ÑùÆ·ÖÐÌúÔªËØÓëÑõÔªËØµÄÖÊÁ¿±ÈÊÇ5£º1£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø