ÌâÄ¿ÄÚÈÝ

2£®Ä³Ð£¿ÎÍâ»î¶¯Ð¡×飬Óû²â¶¨Ò»´ýÂÃÓοª·¢µÄÑÒ¶´ÄÚ¿ÕÆøÖжþÑõ»¯Ì¼µÄÌå»ý·ÖÊý£¨¼ÙÉè¶´ÄÚ¿ÕÆøÖв»º¬³ý¶þÑõ»¯Ì¼ÍâµÄÆäËûËáÐÔÆøÌ壩£®½øÐÐÁËÈçͼʵÑ飺
£¨1£©È¡Ñù£®ËûÃÇ×¼±¸´ÓÑÒ¶´µÄµ×²¿È¡Ñù£¬ÇëÄãÉè¼ÆÓùã¿ÚÆ¿´Ó¶´ÖÐÈ¡»ØÒ»Æ¿¿ÕÆøÑùÆ·µÄ·½·¨£º½«¹ã¿ÚƿװÂúË®£¬¸ÇÉϲ£Á§Æ¬£¬´ø½ø¶´ÖУ¬½«Ë®µ¹µô£¬²Á¸ÉÆ¿ÄÚ£¬¸ÇÉϲ£Á§Æ¬¼´¿É£»
£¨2£©²â¶¨ÓÃ150mLµÄ×¢ÉäÆ÷´Ó¹ã¿ÚÆ¿ÖгéÈ¡100mLÆøÑù£¬°´ÉÏͼËùʾµÄ×°ÖýøÐÐʵÑ飻
ÈôÒÒ×°ÖÃÖÐNaOHÈÜÒºÄÜÎüÊÕ¶þÑõ»¯Ì¼ÆøÌ壬ÇÒʵÑé½áÊøºó£¬Á¿Í²ÄÚË®µÄÌå»ýΪ99mL£¬´ËÊý¾ÝÊÇCµÄÌå»ýÊý£¨ÓÃÐòºÅÌîд£©
A£®¶þÑõ»¯Ì¼ B£®µªÆøºÍÑõÆøµÄ»ìºÏÆøÌå    C£®¿ÕÆøÖгý¶þÑõ»¯Ì¼ÍâµÄËùÓÐÆøÌå
£¨3£©¼ÆË㣺¶´µ×¿ÕÆøÖжþÑõ»¯Ì¼µÄÌå»ý·ÖÊýΪ1%£»
£¨4£©ÎªÓªÔì¸üºÃµÄÂÃÓλ·¾³£¬ÈÃÑÒ¶´ÏòÓοͿª·¢£¬ÄãÈÏΪӦ²ÉÈ¡ÄÄЩ´ëÊ©À´½µµÍ¸ÃÑÒ¶´ÄÚ¶þÑõ»¯Ì¼µÄº¬Á¿£ºÓÃͨ·ç¹Ü¹ÄÈë¶´ÍâµÄ¿ÕÆø£®

·ÖÎö £¨1£©¸ù¾ÝÅÅË®·¨ÊÕ¼¯ÆøÌ忼ÂÇ£»£¨2£©¸ù¾ÝÇâÑõ»¯ÄÆÎüÊÕÁË¿ÕÆøÖеĶþÑõ»¯Ì¼£¬Ê£ÓàµÄÆøÌå¾ÍÊdzýÈ¥¶þÑõ»¯Ì¼Ê£Óà¿ÕÆøÖеijɷ֣»£¨3£©¸ù¾ÝÁ¿Í²ÖÐË®µÄÌå»ý¾ÍÊdzýÈ¥¶þÑõ»¯Ì¼Ê£Óà¿ÕÆøµÄÌå»ý£¬ÓÃ×ÜÌå»ý¼õÈ¥Á¿Í²ÖÐË®µÄÌå»ý£¬¾ÍÊǶþÑõ»¯Ì¼µÄÌå»ý£»ÔÙ½øÐмÆË㣻£¨4£©ÎªÁ˽µµÍ¶´ÄÚ¶þÑõ»¯Ì¼µÄº¬Á¿£¬ÎÒÃÇ¿ÉÒÔͨ¹ý¸ÄÉÆ¶´ÄÚÍâ¿ÕÆøÁ÷ͨ£¬À´´ïµ½Ä¿µÄ£®

½â´ð ½â£º£¨1£©ÎªÁË·ÀÖ¹°Ñ¶´ÍâµÄÆøÌå´øµ½¶´ÖУ¬±ØÐëÏȽ«¹ã¿ÚƿװÂúË®£¬¸ÇÉϲ£Á§Æ¬ºó´ø½ø¶´ÖУ¬½«Ë®µ¹µô£¬ÒòΪ¶þÑõ»¯Ì¼ÄÜÈÜÓÚË®£¬ÎªÁ˼õÉÙʵÑéÎó²î£¬±ØÐëÒª½«¹ã¿ÚÆ¿ÄÚ²ÐÁôµÄË®·Ö²Á¸É£¬È»ºóÔÙ¸ÇÉϲ£Á§Æ¬£¬¼´¿É£®
£¨2£©ÇâÑõ»¯ÄÆÊÇΪÁËÎüÊÕÆøÌåÖеÄCO2Ê£ÏÂµÄÆøÌå½øÈë×°ÖñûÖУ¬ÅÅË®·¨ÊÕ¼¯£¬ÅÅ¿ªµÄË®½øÈëÁ¿Í²ÄÚ£¬ËùÒÔÁ¿Í²ÄÚµÄË®Ï൱ÓÚÊÇ¿ÕÆøÖгýCO2ÍâµÄËùÓÐÆøÌåÌå»ý£®
£¨3£©¶´µ×¿ÕÆøÖÐCO2µÄÌå»ý·ÖÊýΪ$\frac{100mL-99mL}{100mL}¡Á100%$=1%
£¨4£©ÎªÁ˽µµÍ¶´ÄÚ¶þÑõ»¯Ì¼µÄº¬Á¿£¬ÎÒÃÇ¿ÉÒÔͨ¹ý¸ÄÉÆ¶´ÄÚÍâ¿ÕÆøÁ÷ͨ£¬À´´ïµ½Ä¿µÄ£®ÀýÈç¿ÉÒÔÓÃͨ·ç¹Ü¹ÄÈë¶´ÍâµÄ¿ÕÆø£®
¹Ê´ð°¸ÊÇ£º£¨1£©½«¹ã¿ÚƿװÂúË®£¬¸ÇÉϲ£Á§Æ¬£¬´ø½ø¶´ÖУ¬½«Ë®µ¹µô£¬²Á¸ÉÆ¿ÄÚ£¬¸ÇÉϲ£Á§Æ¬¼´¿É£»
£¨2£©C
£¨3£©1%
£¨4£©ÓÃͨ·ç¹Ü¹ÄÈë¶´ÍâµÄ¿ÕÆø£¨ºÏÀí¾ÍÐУ©£®

µãÆÀ ½â´ð±¾Ìâ¹Ø¼üÊÇÒªÖªµÀÅÅË®·¨²âÆøÌåÌå»ýµÄ·½·¨£¬ÄÜ´ÓÌâ¸ÉÖÐÌáÈ¡ÓÐÓÃÐÅÏ¢£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
17£®ÊµÑéÊÒ³£ÀûÓÃÒÔÏÂ×°ÖÃÍê³ÉÆøÌåÖÆ±¸¼°ÐÔÖÊʵÑ飮Çë»Ø´ð£º

£¨1£©Ö¸³ö±àºÅÒÇÆ÷µÄÃû³Æ£º¢Ù¾Æ¾«µÆ£¬¢Ú³¤¾±Â©¶·£®
£¨2£©ÒÔÉÏA£¨´ÓA-EÖÐÑ¡Ôñ£©×°ÖÃÓÐÒ»´¦Ã÷ÏԵĴíÎó£¬Çë¼ÓÒÔ¸ÄÕýµ¼Æø¹ÜÉÔ΢¶³öÏðƤÈû¼´¿É£®ÀûÓøÄÕýºóµÄ×°ÖüÌÐøÍê³ÉºóÃæµÄʵÑ飮
£¨3£©ÓûʹÓøßÃÌËá¼ØÖÆÈ¡ÑõÆø£¬Ó¦Ñ¡ÔñµÄ·¢Éú×°ÖÃÊÇA£¬ÊÕ¼¯×°ÖÃÑ¡ÓÃC»òE£¬·´Ó¦Ô­ÀíÓû¯Ñ§·½³Ìʽ±íʾΪ2KMnO4$\frac{\underline{\;\;¡÷\;\;}}{\;}$K2MnO4+MnO2+O2¡ü£»Îª·ÀÖ¹¸ßÃÌËá¼Ø·ÛÄ©½øÈëµ¼¹Ü£¬Ó¦²ÉÈ¡µÄ´ëÊ©ÊÇÔÚÊԹܿڷÅÒ»ÍÅÃÞ»¨£»ÈôʹÓÃC×°ÖÃÊÕ¼¯ÑõÆø£¬ÊµÑé½áÊøÊ±£¬Ó¦ÏÈ´ÓË®²ÛÖÐÒÆ³öµ¼Æø¹Ü£¬ÔÙϨÃð¾Æ¾«µÆ£¬Ô­ÒòÊÇ·Àֹˮ²ÛÖÐË®µ¹Á÷£¬Õ¨ÁÑÊԹܣ®
£¨4£©Áò»¯ÇâÊÇÒ»ÖÖÎÞÉ«ÇÒÓгô¼¦µ°ÆøÎ¶µÄÆøÌ壬ÃÜ¶È±È¿ÕÆøµÄ´ó£¬ÄÜÈÜÓÚË®£¬¿ÉÐγÉÒ»ÖÖËáÈÜÒº--ÇâÁòËᣮʵÑéÊÒÓùÌÌåÁò»¯ÑÇÌú¸úÏ¡ÁòËá·´Ó¦ÖÆÈ¡Áò»¯ÇâÆøÌ壮ÊԻشð£º
¢ÙÁò»¯ÇâÆøÌå¾ßÓгô¼¦µ°ÆøÎ¶£¬ÕâÊÇÁò»¯ÇâµÄÎïÀí£¨Ìî¡°ÎïÀí¡±»ò¡°»¯Ñ§¡±£©ÐÔÖÊ£®
¢ÚʵÑéÊÒÖÆÈ¡H2SÆøÌåʱ£¬·¢Éú×°ÖÃӦѡÓÃB£¬ÊÕ¼¯×°ÖÃӦѡÓÃE£¨ÌîÒÇÆ÷±àºÅ£©£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø