题目内容
计算(能简算要简算)及解方程
![]() ![]() ![]() ![]() | ( ![]() ![]() ![]() | ![]() | ![]() |
![]() | ![]() ![]() | x×5=100×![]() |
解:
(1)
÷
+
×
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(2)(
+
-
)×24,
=
×24+
×24-
×24,
=18+12-14,
=30-14,
=16;
(3)
,
=
,
=
÷
,
=
;
(4)
,
=
×(1+0.36+0.64),
=
×2,
=
;
(5)
=12,
×
=12×
,
x=3,
x÷
=3÷
,
x=
;
(6)
x+
x=15,
x=15,
x÷
=15÷
,
x=18;
(7)x×5=100×
,
x×5=75,
x×5÷5=75÷5,
x=15.
分析:(1)把
÷
改写为
×
,然后再根据乘法分配律进行简算;
(2)根据乘法分配律进行简算;
(3)先算小括号里面的减法,再算中括号里面的除法,最后算括号外面的除法;
(4)根据乘法分配律进行简算;
(5)等式的两边同时乘
,然后等式的两边同时除以
;
(6)先计算
x+
x=
x,然后等式的两边同时除以
;
(7)先计算100×
=75,然后等式的两边同时除以5即可.
点评:四则混合运算,先弄清运算顺序,然后再进一步计算即可,能简算的要简算;解方程,要根据等式的性质进行解答.
(1)
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=
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=(
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=1×
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=
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(2)(
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=
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=18+12-14,
=30-14,
=16;
(3)
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=
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=
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=
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(4)
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=
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=
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=
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(5)
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x=
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(6)
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x=18;
(7)x×5=100×
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x×5=75,
x×5÷5=75÷5,
x=15.
分析:(1)把
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(2)根据乘法分配律进行简算;
(3)先算小括号里面的减法,再算中括号里面的除法,最后算括号外面的除法;
(4)根据乘法分配律进行简算;
(5)等式的两边同时乘
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(6)先计算
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(7)先计算100×
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点评:四则混合运算,先弄清运算顺序,然后再进一步计算即可,能简算的要简算;解方程,要根据等式的性质进行解答.
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