题目内容
计算(能简算要简算)及解方程
|
(
|
|
| ||||||||||||||||||||||||||
|
|
x×5=100×
|
分析:(1)把
÷
改写为
×
,然后再根据乘法分配律进行简算;
(2)根据乘法分配律进行简算;
(3)先算小括号里面的减法,再算中括号里面的除法,最后算括号外面的除法;
(4)根据乘法分配律进行简算;
(5)等式的两边同时乘
,然后等式的两边同时除以
;
(6)先计算
x+
x=
x,然后等式的两边同时除以
;
(7)先计算100×
=75,然后等式的两边同时除以5即可.
7 |
9 |
11 |
5 |
7 |
9 |
5 |
11 |
(2)根据乘法分配律进行简算;
(3)先算小括号里面的减法,再算中括号里面的除法,最后算括号外面的除法;
(4)根据乘法分配律进行简算;
(5)等式的两边同时乘
1 |
4 |
2 |
3 |
(6)先计算
2 |
3 |
1 |
6 |
5 |
6 |
5 |
6 |
(7)先计算100×
3 |
4 |
解答:解:
(1)
÷
+
×
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(2)(
+
-
)×24,
=
×24+
×24-
×24,
=18+12-14,
=30-14,
=16;
(3)
÷[1÷(
-
)],
=
÷[1÷
],
=
÷
,
=
;
(4)
+0.36×
+
×0.64,
=
×(1+0.36+0.64),
=
×2,
=
;
(5)
x÷
=12,
x÷
×
=12×
,
x=3,
x÷
=3÷
,
x=
;
(6)
x+
x=15,
x=15,
x÷
=15÷
,
x=18;
(7)x×5=100×
,
x×5=75,
x×5÷5=75÷5,
x=15.
(1)
7 |
9 |
11 |
5 |
2 |
9 |
5 |
11 |
=
7 |
9 |
5 |
11 |
2 |
9 |
5 |
11 |
=(
7 |
9 |
2 |
9 |
5 |
11 |
=1×
5 |
11 |
=
5 |
11 |
(2)(
3 |
4 |
1 |
2 |
7 |
12 |
=
3 |
4 |
1 |
2 |
7 |
12 |
=18+12-14,
=30-14,
=16;
(3)
4 |
5 |
5 |
8 |
1 |
4 |
=
4 |
5 |
3 |
8 |
=
4 |
5 |
8 |
3 |
=
3 |
10 |
(4)
5 |
6 |
5 |
6 |
5 |
6 |
=
5 |
6 |
=
5 |
6 |
=
5 |
3 |
(5)
2 |
3 |
1 |
4 |
2 |
3 |
1 |
4 |
1 |
4 |
1 |
4 |
2 |
3 |
2 |
3 |
2 |
3 |
2 |
3 |
x=
9 |
2 |
(6)
2 |
3 |
1 |
6 |
5 |
6 |
5 |
6 |
5 |
6 |
5 |
6 |
x=18;
(7)x×5=100×
3 |
4 |
x×5=75,
x×5÷5=75÷5,
x=15.
点评:四则混合运算,先弄清运算顺序,然后再进一步计算即可,能简算的要简算;解方程,要根据等式的性质进行解答.
练习册系列答案
相关题目