题目内容
下面各题怎样简便就怎样计算
①5.02-1.37-2.63
②[
-(
-
)÷
]÷
③
+
+
+
+…++
.
①5.02-1.37-2.63
②[
3 |
5 |
2 |
3 |
1 |
4 |
5 |
6 |
1 |
10 |
③
1 |
1×2 |
1 |
2×3 |
1 |
3×4 |
1 |
4×5 |
1 |
99×100 |
分析:(1)5.02-1.37-2.63,根据减法的运算性质,a-b-c=a-(b+c),由此进行简算;
(2)[
-(
-
)÷
]÷
,直接根据分数四则运算的运算顺序,按照分数四则运算的计算法则进行计算;
(3)
+
+
+
+…++
.根据分数的拆项原理,可以把每一个分数拆分为两个单位分数的差来计算,通过拆分,使得一部分相互抵消,从而简便计算;
(2)[
3 |
5 |
2 |
3 |
1 |
4 |
5 |
6 |
1 |
10 |
(3)
1 |
1×2 |
1 |
2×3 |
1 |
3×4 |
1 |
4×5 |
1 |
99×100 |
解答:解:(1)5.02-1.37-2.63,
=5.02-(1.37+2.63),
=5.02-4,
=1.02;
(2)[
-(
-
)÷
]÷
,
=[
-
×
]÷
,
=[
-
]÷
,
=
×
,
=1;
(3)
+
+
+
+…++
,
=(
-
)+(
-
)+(
-
)+(
-
)+…+(
-
),
=1-
,
=
.
=5.02-(1.37+2.63),
=5.02-4,
=1.02;
(2)[
3 |
5 |
2 |
3 |
1 |
4 |
5 |
6 |
1 |
10 |
=[
3 |
5 |
5 |
12 |
6 |
5 |
1 |
10 |
=[
3 |
5 |
1 |
2 |
1 |
10 |
=
1 |
10 |
10 |
1 |
=1;
(3)
1 |
1×2 |
1 |
2×3 |
1 |
3×4 |
1 |
4×5 |
1 |
99×100 |
=(
1 |
1 |
1 |
2 |
1 |
2 |
1 |
3 |
1 |
3 |
1 |
4 |
1 |
4 |
1 |
5 |
1 |
99 |
1 |
100 |
=1-
1 |
100 |
=
99 |
100 |
点评:此题主要考查小数、分数四则混合运算,解答时要灵活应用运算定律、运算性质进行简算.
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