7.在数列{an}中,a1=1,an+2+ancosnπ=1,记Sn是数列{an}的前n项和,则$\frac{{S}_{120}}{{a}_{61}}$等于( )
| A. | 930 | B. | 1520 | C. | 60 | D. | 61 |
6.已知在△ABC中,向量$\overrightarrow{m}$=(-cosA,sinA),$\overrightarrow{n}$=(cosC,sinC),$\overrightarrow{m}$•$\overrightarrow{n}$=cos2B,若AC=6,且$\overrightarrow{BA}$•$\overrightarrow{BC}$=-18,则AB+AC等于( )
| A. | 3$\sqrt{2}$ | B. | 3$\sqrt{6}$ | C. | 12 | D. | 6$\sqrt{2}$ |
5.设正项等差数列{an}的前n项和为Sn,已知S5=40,且a4,a8-1,a15成等比数列,则S15等于( )
| A. | 225 | B. | 345 | C. | 350 | D. | 535 |
4.△ABC的三边成等差数列,最大边长为26,且它所对角的余弦值为$\frac{1}{6}$,则最小边长为( )
| A. | 18 | B. | 24 | C. | 12 | D. | 16 |
3.数列{an}满足anan+1-an+1=-1,a2016=-1,则a361等于( )
| A. | -1 | B. | $\frac{1}{2}$ | C. | 1 | D. | 2 |
2.已知向量|$\overrightarrow{a}$|=2,(2$\overrightarrow{a}$-$\overrightarrow{b}$)•($\overrightarrow{a}$+2$\overrightarrow{b}$)=-1,向量$\overrightarrow{a}$,$\overrightarrow{b}$的夹角为$\frac{2π}{3}$,则|$\overrightarrow{b}$|等于( )
| A. | 1 | B. | 3 | C. | $\frac{3}{2}$ | D. | $\frac{1}{2}$ |
18.三点(3,10),(7,20),(11,24)的回归方程是( )
0 252589 252597 252603 252607 252613 252615 252619 252625 252627 252633 252639 252643 252645 252649 252655 252657 252663 252667 252669 252673 252675 252679 252681 252683 252684 252685 252687 252688 252689 252691 252693 252697 252699 252703 252705 252709 252715 252717 252723 252727 252729 252733 252739 252745 252747 252753 252757 252759 252765 252769 252775 252783 266669
| A. | $\widehat{y}$=5-17x | B. | $\widehat{y}$=-17+5x | C. | $\widehat{y}$=17+5x | D. | $\widehat{y}$=17-5x |