摘要:(1) = . = .(2)推算OA10的长.
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OA1=1; OA2=
12+12 |
2 |
1 |
2 |
1 |
2 |
OA3=
2+12 |
3 |
1 |
2 |
2 |
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2 |
OA4=
3+12 |
4 |
1 |
2 |
3 |
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2 |
…
问:(1)推算OA10的长度.
(2)推算:S10的值.
(3)求OAn的长度(用含n的代数式表示)

(
1 |
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2 |
(
2 |
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2 |
(
3 |
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2 |
(1)请用含n(n是正整数)的等式表示上述变化规律;
(2)推算出OA10的长;
(3)求出S12+S22+S22+…+S102的值. 查看习题详情和答案>>

OA22=(
1 |
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2 |
OA32=12+(
2 |
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2 |
OA42=12+(
3 |
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2 |
…
(1)推算出OA10的长;
(2)若一个三角形的面积是
5 |