摘要:20. 已知数列{an}的前n项和为Sn,若a1=3,点(Sn.Sn+1)在直线上. an (Ⅰ)求证:数列是等差数列, (Ⅱ)若数列{bn}满足bn=an·2 .求数列{bn}的前n项和Tn, (Ⅲ)设Cn=.求证:C1+ C2+-+Cn>.
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(本小题满分12分)已知数列{an}的前n项和为Sn, 且满足条件:4S n =
+ 4n – 1 , nÎN*.
(1) 证明:(a n– 2)2 –
=0 (n ³ 2);(2) 满足条件的数列不惟一,试至少求出数列{an}的的3个不同的通项公式 .
(本小题满分12分)
已知数列{an}的前n项和为Sn, Sn+1="4an+2," a1="1," bn=an+1-2an(n∈N*)
(1) 求数列{bn}的前n项和Tn.
(2)求 an![]()