摘要:DE∥ AC1 AC1 ∥平面CDB1(2) 作BF ⊥B1D于F, 连结EF,
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侧棱A1A垂直于底面ABC,AC=3,BC=4,AB=5,点D是AB的中点,
(1)求证:AC1∥平面CDB1;(2)求证:AC⊥BC1.
(1)求异面直线BC与AC1的夹角;
(2)求证:AC1∥平面CDB1.
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