摘要:(Ⅱ)因为b2=1, bn+2- b=(bn+1-2n)(bn+1+2n+1)- b=2n+1?bn-1-2n?bn+1-2n?2n+1=2n(bn+1-2n+1)=2n(bn+2n-2n+1)=2n(bn-2n)=-=2n(b1-2)=-2n〈0.所以bn-bn+2<b2n+1

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