摘要:(2)∵Sn=2n+×2=n2+n,
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数列{an}前n项和为Sn=n2+2n,等比数列{bn}各项为正数,且b1=1,{ban}是公比为64的等比数列.
(1)求数列{an}与{bn}的通项公式;
(2)证明:
+
+…+
<
.
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(1)求数列{an}与{bn}的通项公式;
(2)证明:
| 1 |
| S1 |
| 1 |
| S2 |
| 1 |
| Sn |
| 3 |
| 4 |
数列{an}前n项和为Sn=n2+2n,等比数列{bn}各项为正数,且b1=1,{ban}是公比为64的等比数列.
(1)求数列{an}与{bn}的通项公式;
(2)证明:
+
+…+
<
.
查看习题详情和答案>>
(1)求数列{an}与{bn}的通项公式;
(2)证明:
| 1 |
| S1 |
| 1 |
| S2 |
| 1 |
| Sn |
| 3 |
| 4 |