摘要:2.若f[g(x)] = 9x+3.且g(x) = 3x+1.则f(x)的解析式为 ( ) A.3x B.3 C.9(3x+1) +1 D.3(9x+3) +1
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设f(x)=g(x)是二次函数.若f[g(x)]的值域是[0,+∞),则g(x)的值域是 ( )
A.(-∞,-1]∪[1,+∞) B.(-∞,-1]∪[0,+∞)
C.[0,+∞) D.[1,+∞)
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