摘要:如图所示.将小球以Ek0的初动能自倾角为θ的斜面顶端水平抛出.不计空气阻力.当它落到斜面上时.小球动能表达式为Ekt= .如果Ek0=6 J.θ=300 那么Ekt= J.
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(4tan2θ+1)EK0
(4tan2θ+1)EK0
.如果EK0=6J,θ=30°那么EKt14
14
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