ÌâÄ¿ÄÚÈÝ

ÈçͼΪһװÖõÄʾÒ⣬СľͰabcdµÄÖÊÁ¿ÎªM =0.18kg£¬¸ßL = 0.2m£¬ÆäÉÏÑØabÀëµ²°åEµÄÊúÖ±¾àÀëh = 0.8m£¬ÔÚСľͰÄÚ·ÅÓÐÒ»ÖÊÁ¿m=0.02kgµÄСʯ¿éP£¨ÊÓΪÖʵ㣩¡£ÏÖͨ¹ýϸÉþ¶ÔСľͰʩ¼ÓÒ»¸öÊúÖ±ÏòÉϵĺãÁ¦F£¬Ê¹Ð¡Ä¾Í°Óɾ²Ö¹¿ªÊ¼ÏòÉÏÔ˶¯£¬Ð¡Ä¾Í°µÄÉÏÑØabÓëµ²°åEÏàÅöºó±ãÁ¢¼´Í£Ö¹Ô˶¯£¬Ð¡Ê¯¿éPÉÏÉýµÄ×î´ó¸ß¶ÈÇ¡ºÃÓëabÏàƽ¡£

Çó£º
¢ÙÀ­Á¦FµÄ´óС£»
¢ÚСʯ¿éPÓɾ²Ö¹¿ªÊ¼µ½×î¸ßµãµÄ¹ý³ÌÖУ¬Ð¡Ä¾Í°abcd¶ÔËü×öµÄ¹¦¡££¨È¡g = 10m/s2£¬¿ÕÆø×èÁ¦ºÍ¶¨»¬ÂÖĦ²Á¾ùºöÂÔ²»¼Æ£©¡£
(1)  (2)

ÊÔÌâ·ÖÎö£º£¨1£©Ð¡Ä¾Í°Í£Ö¹Ô˶¯£¬Ð¡Ê¯¿éP×÷ÊúÖ±ÉÏÅ×Ô˶¯£¬´ËʱËüÃǵÄËÙ¶ÈΪv£º
            £¨3·Ö£©
¶ÔСľͰ£º        £¨3·Ö£©
¶ÔÕûÌ壺          £¨4·Ö£©
£¨2£©Ð¡Ê¯¿éPÓɾ²Ö¹¿ªÊ¼µ½×î¸ßµãµÄ¹ý³ÌÖУ¬Óɶ¯Äܶ¨ÀíµÃ£º
            £¨6·Ö£©
µãÆÀ£ºÕûÌå·¨ºÍ¸ôÀë·¨ÔÚÎÒÃÇ·ÖÎöÎÊÌâʱ£¬ÊÇÒ»Öַdz£±ã½ÝÓÐÓõķ½·¨£¬²¢ÇÒÒ²ÊÇÏÖÔÚ¿¼ÊÔµÄÒ»¸öÈȵã
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø