题目内容
一列简谐横波沿x轴传播,频率为5 Hz,某时刻的波形如图所示.介质中质点A的平衡位置在距原点8 cm处,质点B在距原点16 cm处,从图象对应时刻开始计时,质点B的运动状态与图示时刻质点A的运动状态相同所需的最短时间可能是( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241426085843862.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241426085843862.png)
A.0.08 s | B.0.12 s |
C.0.14 s | D.0.16 s |
AB
考查波的图象及其对图象的理解和应用.由题意可知,周期T=
="0.2" s,由图象可知该波的波长λ="0.2" m,所以波速v=
="1" m/s.当波沿x轴负方向传播时,最短距离sBA="0.08" m,所以最短时间t1=
="0.08" s,A对;当波沿x轴正方向传播时,最短距离sBA="0.12" m,所以最短时间t2=
="0.12" s,B对;C?D均错.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824142608740347.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824142608803427.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824142608881469.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824142608881469.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
练习册系列答案
相关题目