ÌâÄ¿ÄÚÈÝ

ÔÚijһÕæ¿Õ¿Õ¼äÄÚ½¨Á¢xOy×ø±êϵ£¬´ÓÔ­µãO´¦ÏòµÚIÏóÏÞ·¢ÉäÒ»ºÉÖʱȵĴøÕýµçµÄÁ£×Ó£¨ÖØÁ¦²»¼Æ£©£®ËٶȴóСv0=103 m/s¡¢·½ÏòÓëxÖáÕý·½Ïò³É300½Ç£®
(1)ÈôÔÚ×ø±êϵyÖáÓÒ²à¼ÓÓÐÔÈÇ¿´Å³¡ÇøÓò£¬ÔÚµÚIÏóÏÞ£¬´Å³¡·½Ïò´¹Ö±xOyƽÃæÏòÍ⣻ÔÚµÚ¢ôÏóÏÞ£¬´Å³¡·½Ïò´¹Ö±xOyƽÃæÏòÀ´Å¸ÐӦǿ¶ÈΪB=1 T£¬Èçͼ(a£©Ëùʾ£¬ÇóÁ£×Ó´ÓOµãÉä³öºó£¬µÚ2´Î¾­¹ýxÖáʱµÄ×ø±êx1.
  
(2)Èô½«ÉÏÊö´Å³¡¾ù¸ÄΪÈçͼ(b£©ËùʾµÄÔÈÇ¿´Å³¡£¬ÔÚt=0µ½t=sʱ£¬´Å³¡·½Ïò´¹Ö±ÓÚxOyƽÃæÏòÍ⣻ÔÚt=sµ½t=sʱ£¬´Å³¡·½Ïò´¹Ö±ÓÚxOyƽÃæÏòÀ´Ëºó¸Ã¿Õ¼ä²»´æÔڴų¡£¬ÔÚt=0ʱ¿Ì£¬Á£×ÓÈÔ´ÓOµãÒÔÓëÔ­À´ÏàͬµÄËÙ¶Èv0ÉäÈ룬ÇóÁ£×Ó´ÓOµãÉä³öºóµÚ2´Î¾­¹ýxÖáʱµÄ×ø±êx2.
½â£º(1)Á£×ÓÔÚxÖáÉÏ·½ºÍÏ·½µÄ´Å³¡ÖÐ×ö°ë¾¶ÏàͬµÄÔÈËÙÔ²ÖÜÔ˶¯£¬ÆäÔ˶¯¹ì¼£Èçͼ (a£©Ëùʾ£®ÉèÁ£×ӵĹìµÀ°ë¾¶r£¬ÓÐÓɼ¸ºÎ¹Øϵ֪Á£×ÓµÚ¶þ´Î¾­¹ýxÖáµÄ×ø±êΪx1=2r=0. 2 m.(2)ÉèÁ£×ÓÔڴų¡ÖÐ×öÔ²ÖÜÔ˶¯µÄÖÜÆÚΪT.Ôò.¾ÝÌâÒ⣬֪Á£×ÓÔÚt=0µ½tÄÚºÍÔÚtµ½tʱ¼äÄÚÔڴų¡ÖÐת¹ýµÄÔ²»¡Ëù¶ÔµÄÔ²ÐĽǾùΪ£¬Á£×ÓµÄÔ˶¯¹ì¼£Ó¦Èçͼ (b£©Ëùʾ¡£Óɼ¸ºÎ¹ØϵµÃx2=6r=0.6 m¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø