题目内容
如图所示,半圆玻璃砖的半径R=10cm,折射率为n=
,直径AB与屏幕垂直并接触于A点.激光a以入射角i=30°射向半圆玻璃 砖的圆心O,结果在水平屏幕MN上出现两个光斑.则两个光斑之间的距离.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241242058282785.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124205812341.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241242058282785.png)
A.![]() | B.![]() | C.![]() | D.![]() |
C
画出如图光路图,设折射角为r,根据折射定律
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241242059538761.png)
解得
,由几何知识得,ΔOPQ为直角三角形,所以两个光斑PQ之间的距离
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241242059991105.png)
解得![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124206015821.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124205921658.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241242059538761.png)
解得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124205968427.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241242059991105.png)
解得
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124206015821.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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