题目内容
光在某介质中的传播速度是2.122×108m/s,当光线以30°入射角,由该介质射入空气时,折射角为多少?
解:由介质的折射率与光速的关系得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124006238286.gif)
又根据介质折射率的定义式得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124006254341.gif)
r为在空气中光线、法线间的夹角即为所求,i为在介质中光线与法线间的夹角30°。由(1)、(2)两式解得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124006316697.gif)
所以r=45°
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124006238286.gif)
又根据介质折射率的定义式得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124006254341.gif)
r为在空气中光线、法线间的夹角即为所求,i为在介质中光线与法线间的夹角30°。由(1)、(2)两式解得:
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824124006316697.gif)
所以r=45°
略
![](http://thumb2018.1010pic.com/images/loading.gif)
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