题目内容
如图1所示,两轮用皮带传动,皮带不打滑,图中有A、B、C三点,这三点所在处半径rA>rB=rC,则这三点的向心加速度aA、aB、aC的关系是 ( )
A.aA=aB=aC
B.aC>aA>aB
C.aC<aA<aB
D.aC=aB>aA
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241413087084322.png)
A.aA=aB=aC
B.aC>aA>aB
C.aC<aA<aB
D.aC=aB>aA
C
皮带传动且不打滑,A点与B点线速度相同,由a=
有a∝
,所以aA<aB;A点与C点共轴转动,角速度相同,由a=ω2r知a∝r,所以有aA>aC,所以aC<aA<aB,可见选项C正确.
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824141308817424.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824141308942316.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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