ÌâÄ¿ÄÚÈÝ
17£®ÈçͼËùʾ£¬ÔÚxOyƽÃæµÄµÚÒ»ÏóÏÞÄÚ£¬·Ö²¼ÓÐÑØxÖḺ·½ÏòµÄ³¡Ç¿E=4¡Á104N/CµÄÔÈÇ¿µç³¡£¬µÚËÄÏóÏÞÄÚ·Ö²¼Óд¹Ö±Ö½ÃæÏòÀïµÄ´Å¸ÐӦǿ¶ÈB1=0.2TµÄÔÈÇ¿´Å³¡£¬µÚ¶þ¡¢ÈýÏóÏÞÄÚ·Ö²¼Óд¹Ö±Ö½ÃæÏòÀïµÄ´Å¸ÐӦǿ¶ÈB2µÄÔÈÇ¿´Å³¡£®ÔÚxÖáÉÏÓÐÒ»¸ö´¹Ö±ÓÚyÖáµÄƽ°åOM£¬Æ½°åÉÏ¿ªÓÐÒ»¸öС¿×P£®yÖḺ·½ÏòÉϾàOµã$\sqrt{3}$cmµÄÁ£×ÓÔ´S¿ÉÒÔÏòµÚËÄÏóÏÞƽÃæÄÚ¸÷¸ö·½Ïò·¢Éä¦ÁÁ£×Ó£¬ÇÒOS£¾OP£®¼ÙÉè·¢ÉäµÄ¦ÁÁ£×ÓËٶȴóСv¾ùΪ2¡Á105m/s£¬³ýÁË´¹Ö±Öáxͨ¹ýPµãµÄ¨¢Á£×Ó¿ÉÒÔ½øÈëµç³¡£¬ÆäÓà´òµ½Æ½°åÉϵĨ¢Á£×Ó¾ù±»ÎüÊÕ£®ÒÑÖª¦ÁÁ£×Ó´øÕýµç£¬±ÈºÉΪ$\frac{q}{m}$=5¡Ál07C/kg£¬ÖØÁ¦²»¼Æ£¬Ç󣺣¨1£©¦ÁÁ£×ÓÔÚµÚËÄÏóÏ޵Ĵų¡ÖÐÔ˶¯Ê±µÄ¹ìµÀ°ë¾¶£»
£¨2£©ÎªÊ¹ÆäÓà¦ÁÁ£×Ó²»ÄܽøÈëµç³¡£¬Æ½°åOMµÄ³¤¶ÈÖÁÉÙÊǶ೤£¿
£¨3£©¾¹ýPµã½øÈëµç³¡ÖÐÔ˶¯µÄ¦ÁÁ£×Ó£¬µÚÒ»´Îµ½´ïyÖáµÄλÖÃÓëOµãµÄ¾àÀ룻
£¨4£©ÒªÊ¹À뿪µç³¡µÄ¦ÁÁ£×ÓÄܻص½Á£×ÓÔ´S´¦£¬´Å¸ÐӦǿ¶ÈB2ӦΪ¶à´ó£¿
·ÖÎö £¨1£©ÓÉÂåÂØ×ÈÁ¦ÌṩÏòÐÄÁ¦£¬´Ó¶øµÃµ½ÔÚºÍËÄÏóÏÞ×öÔÈËÙÔ²ÖÜÔ˶¯µÄ¹ìµÀ°ë¾¶£®
£¨2£©µ±Á£×ÓÔڴų¡ÖÐÔ˶¯µÄÏÒ³¤µÈÓÚÖ±¾¶Ê±£¬¿ÉÒԵóöOMµÄ×îС³¤¶È£®
£¨3£©´ÓPµã½øÈëµç³¡µÄÁ£×Ó×öÀàƽÅ×Ô˶¯£¬ÓÉÀàƽÅ×Ô˶¯ÏàÓ¦¹æÂɾÍÄÜÇó³öÀàƽÅ×Ô˶¯µÄÔÈËÙλÒÆ£®
£¨4£©Á£×ÓÀ뿪µç³¡ºó½øÈëB2´Å³¡×öÔÈËÙÔ²ÖÜÔ˶¯£¬ÏÈÇó³öÀ뿪µç³¡´Å³¡µÄËٶȷ½Ïò£¬µ±Ôٴλص½yÖáʱ¸ù¾ÝÔ²ÖÜÔ˶¯µÄ¶Ô³ÆÐÔÓëyÖáµÄ¼Ð½ÇÏàµÈ£¬µ«Òª×¢ÒâµÄÊÇ¿ÉÒÔÊÇÖ±½Ó»Øµ½Sµã£¬Ò²¿ÉÄÜÊÇÔÚB1ÖÐƫתºó»Øµ½S´¦£¬ËùÒÔÒª·ÖÁ½ÖÖÇé¿ö½øÐп¼ÂÇ£®Óɳö·¢µãºÍSµãµÄ¾àÀëÇó³ö×öÔ²ÖÜÔ˶¯µÄ°ë¾¶£¬ÔÙÓÉÂåÂØ×ÈÁ¦ÌṩÏòÐÄÁ¦´Ó¶øÇó³öB2
½â´ð ½â£º£¨1£©ÔÚB1´Å³¡ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯£¬ÔòÓУº
${B}_{1}qv=m\frac{{v}^{2}}{r}$
µÃµ½£º$r=\frac{mv}{{B}_{1}q}=0.02m=2cm$
£¨2£©Á£×Ó³öÀ´µÄ×îÔ¶¾àÀëÊÇÏÒ×Ϊֱ¾¶Ê±£¬Óɼ¸ºÎ¹Øϵ¿ÉµÃ£¬L=$\sqrt{£¨2r£©^{2}-{h}^{2}}$=$\sqrt{13}$cm£®
£¨3£©Á£×Ó½øÈëµç³¡ºó×öÀàƽÅ×Ô˶¯£¬
xÖá·½ÏòλÒÆΪ£º$x=\frac{1}{2}a{t}^{2}$
yÖá·½ÏòλÒÆΪ£ºy=vt
¼ÓËÙ¶ÈΪ£º$a=\frac{qE}{m}=2¡Á1{0}^{12}m/{s}^{2}$
ËùÒÔÁ£×Óµ½´ïyÖáλÖÃÓëOµãµÄ¾àÀëΪ£ºy=0.02m
£¨4£©ÉèÁ£×ÓÔÚyÖáÉä³öµç³¡µÄλÖõ½Á£×ÓÔ´SµÄ¾àÀëΪH£¬ÓУº
H=y+h=£¨2+$\sqrt{3}$£©¡Á10-2m
ÉèÁ£×ÓÔÚyÖáÉä³öµç³¡µÄËٶȷ½ÏòÓëyÖáÕý·½Ïò¼Ð½ÇΪ¦È£¬ÓУº
$tan¦È=\frac{at}{v}=1$ ËùÒÔ¦È=45¡ã
$v¡ä=\sqrt{2}v$
·ÖÁ½ÖÖÇé¿ö´¦Àí£º¢ÙÈôÁ£×ÓÀ뿪µç³¡¾B2´Å³¡Æ«×ªºóÖ±½Ó»Øµ½Àë×ÓÔ´´¦£¬ÔòÔÚB2´Å³¡ÖÐÔ²ÖÜ
Ô˶¯°ë¾¶Îª£º$R=\frac{H}{\sqrt{2}}=\frac{2+\sqrt{3}}{\sqrt{2}}¡Á1{0}^{-2}m$
ÓÉ${B}_{2}qv¡ä=m\frac{v{¡ä}^{2}}{R}$ µÃ£º${B}_{2}=\frac{mv¡ä}{qR}=\frac{0.8}{2+\sqrt{3}}T$
¢ÚÁ£×ÓÀ뿪µç³¡¾B2´Å³¡Æ«×ªºó½øÈëB1´Å³¡Æ«×ªÔٻص½Àë×ÓÔ´S´¦£¬Ôò½øÈëB1´Å³¡µÄƫת°ë¾¶
$r¡ä=\sqrt{2}r=2\sqrt{2}¡Á1{0}^{-2}m$
ÔÚB2´Å³¡ÖÐÔ²ÖÜÔ˶¯°ë¾¶Îª£ºR=$\frac{H+\sqrt{2}r¡ä}{\sqrt{2}}=\frac{mv¡ä}{{B}_{2}q}$
½âµÃ£º${B}_{2}=\frac{0.8}{6+\sqrt{3}}T$
´ð£º£¨1£©¨¢Á£×ÓÔÚµÚËÄÏóÏ޵Ĵų¡ÖÐÔ˶¯Ê±µÄ¹ìµÀ°ë¾¶Îª2cm£®
£¨2£©¾¹ýPµã½øÈëµç³¡ÖÐÔ˶¯µÄ¦ÁÁ£×Ó£¬µÚÒ»´Îµ½´ïyÖáµÄλÖÃÓëOµãµÄ¾àÀë0.02m£®
£¨3£©ÒªÊ¹À뿪µç³¡µÄ¦ÁÁ£×ÓÄܻص½Á£×ÓÔ´S´¦£¬´Å¸ÐӦǿ¶ÈB2ӦΪ$\frac{0.8}{2+\sqrt{3}}T$»ò$\frac{0.8}{6+\sqrt{3}}T$£®
µãÆÀ ±¾ÌâµÄÄѵãÔÚÓÚ×îºóÒ»ÎÊ£¬´Óµç³¡À뿪ºóÔٴλص½S´¦£¬ºÃÔڴӵ糡À뿪ʱÓëyÖá³É45¡ã½Ç£¬ÔòÔÚB2ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯ºó»Øµ½yÖáʱÓëyÖáÒ²³É45¡ã½Ç£¬ÕâÑù¾ÍÓɼ¸ºÎ¹ØϵÄÜÇó³öÔÚB2ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯°ë¾¶£¬µ«Òª×¢ÒâµÄÊÇÓпÉÄÜÊǾ¹ýÁ½´ÎÔ²ÖÜÔ˶¯ºóµ½´ïS´¦µÄ£¬ÕâÑùÁ½ÖÖÇé¿öµÄ°ë¾¶²»Ïàͬ£®
A£® | ÏßȦ´ÓͼʾλÖÃת90¡ãµÄ¹ý³Ì´ÅͨÁ¿µÄ±ä»¯ÎªNBS | |
B£® | ÏßȦתµ½ÖÐÐÔÃæλÖÃʱ²úÉúµÄ¸ÐÓ¦µç¶¯ÊÆΪNBS¦Ø | |
C£® | ÏßȦתµ½Í¼Ê¾Î»ÖÃʱ´ÅͨÁ¿µÄ±ä»¯ÂÊΪBS¦Ø | |
D£® | ÏßȦ´ÓͼʾλÖÿªÊ¼¼Æʱ£¬¸ÐÓ¦µç¶¯ÊÆeËæʱ¼ät±ä»¯µÄº¯ÊýΪe=NBS¦Øsin¦Øt |
A£® | ÒºÌåµÄζÈÔ½¸ß£¬²¼ÀÊÔ˶¯Ô½ÏÔÖø | |
B£® | Íâ½ç¶ÔÆøÌå×ö¹¦Ê±£¬ÆÚÄÚÄÜÒ»¶¨»áÔö´ó | |
C£® | µç±ùÏäµÄ¹¤×÷¹ý³Ì±íÃ÷£¬ÈÈÁ¿¿ÉÒÔ´ÓµÍÎÂÎïÌå´«µ½¸ßÎÂÎïÌå | |
D£® | Òº¾§ÏÔʾÆÁÊÇÀûÓÃÁËÒº¾§¶Ô¹â¾ßÓи÷ÏòͬÐÔµÄÌصã | |
E£® | µ±·Ö×Ó¼ä¾àÀër=r0ʱ£¬·Ö×Ó¼ä³âÁ¦µÈÓÚÒýÁ¦£¬Êµ¼Ê±íÏÖ³öµÄ·Ö×ÓÁ¦ÎªÁ㣬·Ö×ÓÊÆÄÜ×îС |
A£® | 30¡ã | B£® | 45¡ã | C£® | 60¡ã | D£® | 90¡ã |