题目内容
一个矩形线圈在匀强磁场中转动产生交流电压为U=220
Sin100πt V,则 …( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633912225.gif)
A.它的频率是50 Hz? |
B.当t=0时,线圈平面与中性面重合 |
C.电压的平均值是220 V? |
D.当![]() |
ABD
对照交流电的电压一般表达式u=Umsin(ωt+φ),ω=2πf,
,可求出f、φ0、U.可见:
;φ=0,有效值220 V,
时,u=220
sin(100π×
)=220
=Um.?
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633944470.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633959767.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633990349.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633912225.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120634022301.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824120633912225.gif)
![](http://thumb2018.1010pic.com/images/loading.gif)
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