题目内容
(7分)某学校实验小组欲测定正方体木块与长木板之间的动摩擦因数,采用如图甲所示的装置,图中长木板水平固定。
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250038395038247.jpg)
(1)实验开始之前某同学用游标卡尺测得正方体边长,读数如图乙所示,则正方体的边长为 cm。
(2)如图丙所示为该组同学实验中得到的一条纸带的一部分,0, 1, 2, 3, 4, 5, 6为计数点,相邻两计数点间还有4个计时点未画出。从纸带上测出
=3.20cm,
=4.52cm,
=8.42cm,
=9.70cm,则木块的加速度大小
= m/s2(保留两位有效数字)。
(3) 该组同学用天平测得木块的质量为M,砝码盘和砝码的总质量为m,则木块与长木板间动摩擦因素
= (重力加速度为g,木块的加速度为
)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250038395038247.jpg)
(1)实验开始之前某同学用游标卡尺测得正方体边长,读数如图乙所示,则正方体的边长为 cm。
(2)如图丙所示为该组同学实验中得到的一条纸带的一部分,0, 1, 2, 3, 4, 5, 6为计数点,相邻两计数点间还有4个计时点未画出。从纸带上测出
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839519300.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839534331.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839550329.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839566326.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839581283.png)
(3) 该组同学用天平测得木块的质量为M,砝码盘和砝码的总质量为m,则木块与长木板间动摩擦因素
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839597301.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839581283.png)
(1)9.015 (2分) (2)1.3 (2分)(3)
(3分)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839722709.png)
试题分析:(1)20分度的游标卡尺的精确度为0.05mm,主尺读数为90mm,游标第3条刻线对的最齐,由游标卡尺的读数规则可读出90.15mm=9.015cm;0, 1, 2, 3, 4, 5, 6为计数点,相邻两计数点间还有4个计时点未画出,T=0.1s,由匀变速直线运动规律
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839737583.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839753670.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839768680.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/201408250038398001033.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839815911.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140825/20140825003839831829.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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