ÌâÄ¿ÄÚÈÝ

18£®ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ£¨¡¡¡¡£©
A£®Ô­×ÓºË${\;}_{Z}^{A}$XÓëë°ºË${\;}_{1}^{2}$H·´Ó¦Éú³ÉÒ»¸ö¦ÁÁ£×ÓºÍÒ»¸öÖÊ×Ó£¬ÓÉ´Ë¿ÉÖªA=3£¬Z=2
B£®²¨¶ûÀíÂ۵ļÙÉèÖ®Ò»ÊÇÔ­×ÓÄÜÁ¿µÄÁ¿×Ó»¯
C£®·ÅÉäÐÔÔªËصİëË¥ÆÚËæζȵÄÉý¸ß¶ø±ä¶Ì
D£®Ä³·ÅÉäÐÔÔªËؾ­¹ý11.4ÌìÓÐ$\frac{7}{8}$µÄÔ­×Ӻ˷¢ÉúÁËË¥±ä£¬¸ÃÔªËصİëË¥ÆÚΪ3.8Ìì
E£®Â¬Éª¸£ÔÚ¦ÁÁ£×ÓÉ¢ÉäʵÑéÖз¢ÏÖÁ˵ç×Ó

·ÖÎö ¸ù¾ÝºË·´Ó¦¹ý³ÌÖеçºÉÊýÊغãÒÔ¼°ÖÊÁ¿ÊýÊغãÇó³öAºÍZ¼´¿É£¬¸ù¾Ý²£¶ûÀíÂÛ¿ÉÖª£¬Ô­×ÓÄÜÁ¿µÄÁ¿×Ó»¯£¬Íâ½ç»·¾³µÄ±ä»¯²»»áÓ°Ïì°ëË¥ÆÚ£¬·ÅÉäÐÔÔªËؾ­¹ýÒ»¸ö°ëË¥ÆÚÓÐÒ»°ëÔ­×Ӻ˷¢ÉúË¥±ä£®

½â´ð ½â£ºA¡¢¦ÁÁ£×ÓµÄÖÊ×ÓÊýÊÇ2£¬ÖÊÁ¿ÊýÊÇ4£¬ÖÊ×ÓµÄÖÊ×ÓÊýÊÇ1£¬ÖÊÁ¿ÊýÊÇ1£¬¸ù¾ÝºËµçºÉÊýÊغãÒÔ¼°ÖÊÁ¿ÊýÊغã¿ÉÖª£¬A=4+1-2=3£¬Z=2+1-1=2£¬¹ÊAÕýÈ·£»
B¡¢²¨¶ûÀíÂ۵ļÙÉèÖ®Ò»ÊÇÔ­×ÓÄÜÁ¿µÄÁ¿×Ó»¯£¬¹ÊBÕýÈ·£»
C¡¢·ÅÉäÐÔÎïÖʵÄζÈÉý¸ß£¬µ«°ëË¥ÆÚÈÔ²»±ä£¬¹ÊC´íÎó£»
D¡¢$\frac{7}{8}$µÄÔ­×Ӻ˷¢ÉúÁËË¥±ä£¬»¹Ê£$\frac{1}{8}$£¬ËµÃ÷¾­¹ýÁË3´ÎË¥±ä£¬Ôò°ëË¥ÆÚΪt=$\frac{11.4}{3}=3.8$Ì죬¹ÊDÕýÈ·£»
E¡¢ÌÀÄ·Ñ·Ê×ÏÈ·¢ÏÖÁ˵ç×Ó£¬¹ÊE´íÎó£»
¹ÊÑ¡£ºABD

µãÆÀ ¿¼²é²£¶ûÀíÂÛµÄÄÚÈÝ£¬ÖªµÀ°ëË¥ÆÚÓÉÔ­×ÓºË×ÔÉíÐÔÖʾö¶¨£¬ÓëÎïÀí»·¾³Î޹أ¬ÄѶȲ»´ó£¬ÊôÓÚ»ù´¡Ì⣮

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø