题目内容
如图所示,甲、乙两冰球运动员为争抢冰球而合理冲撞(可视为正碰),已知甲运动员的质量为60kg,乙运动员的质量为70kg,接触前两运动员相向运动,速度大小均为5m/s,结果甲被撞回,速度大小为2m/s,求冲撞后乙的速度大小和方向。![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241330111934495.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241330111934495.jpg)
v′
=1m/s… 碰前甲速度方向相同
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011209242.png)
取碰前甲的速度方向为正方向,对系统运用动量守恒定律,有:
m
v
-m
v
=-m
v′
+m
v′
………………………………………(2分)
解得v′
=1m/s………………………………………………………………(1分)
方向与碰前甲速度方向相同……………………………………………………(1分)、
m
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011240217.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011240217.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011209242.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011209242.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011240217.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011240217.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011209242.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011209242.png)
解得v′
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824133011209242.png)
方向与碰前甲速度方向相同……………………………………………………(1分)、
![](http://thumb2018.1010pic.com/images/loading.gif)
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