ÌâÄ¿ÄÚÈÝ

ÈçͼËùʾ£¬Õæ¿ÕÊÒÄÚ´æÔÚ¿í¶ÈΪ d = 8 cm µÄÔÈÇ¿´Å³¡ÇøÓò£¬´Å¸ÐӦǿ¶È B = 0.332 T £¬´Å³¡·½Ïò´¹Ö±Ö½ÃæÏòÀï¡£ab ¡¢cd ×ã¹»³¤£¬cd Ϊºñ¶È²»¼ÆµÄ½ð²­£¬½ð²­ÓÒ²àÓÐÒ»ÔÈÇ¿µç³¡ÇøÓò£¬µç³¡Ç¿¶È E = 3.32¡Á105 N/C£¬·½ÏòÓë½ð²­³É37o ¼Ð½Ç¡£½ô°¤±ß½ç ab ·ÅÒ»µã×´·ÅÉäÔ´ s ¡£¿ÉÑØÖ½ÃæÏò¸÷¸ö·½Ïò¾ùÔȵطÅÉä³õËÙÂÊÏàͬµÄ ¦Á Á£×Ó£¬ÒÑÖª¦Á Á£×ÓµÄÖÊÁ¿ m = 6.64¡Á10-27 kg£¬¦Á Á£×ӵĵçºÉÁ¿ q = 3.2 ¡Á10-19 C£¬¦Á Á£×ӵijõËٶȴóС v = 3.2¡Á106 m/s £¬ sin37o = 0.6£¬cos37o = 0.8¡£ÊÔÇó£º

£¨1£© ¦Á Á£×ÓÔڴų¡ÖÐ×÷Ô²ÖÜÔ˶¯µÄ¹ìµÀ°ë¾¶R£»

£¨2£© ½ð²­ cd ±» ¦Á Á£×ÓÉäÖÐÇøÓòµÄ³¤¶È L£»

£¨3£©Éè´òÔÚ½ð²­ÉÏ d ¶ËÀë cd ÖÐÐÄ×îÔ¶µÄ ¦Á Á£×ÓÑØÖ±Ïß´©³ö½ð²­½øÈëµç³¡£¬Ôڵ糡ÖÐÔ˶¯Í¨¹ý N µã£¬ÒÑÖª sN ¡Í ab £¬sN = 40 cm £¬Ôò¸Ã ¦Á Á£×Ó´Ó½ð²­ÉÏ´©³öʱ£¬ËðʧµÄ¶¯ÄÜ ¡÷Ek Ϊ¶àÉÙ ?

½â£¨1£©¦Á Á£×ÓÔÚÔÈÇ¿´Å³¡ÖÐ×öÔÈËÙÔ²ÖÜÔ˶¯£¬ÂåÂ××ÈÁ¦ÌṩÏòÐÄÁ¦£¬¼´ qvB  = m    

         Ôò R =  = 0.2 m = 20 cm ¡£   

£¨2£©Éè cd µÄÖÐÐÄΪO £¬Ïò c ¶ËƫתµÄ ¦Á Á£×Ó£¬µ±Ô²Öܹ켣Óë cd ÏàÇÐʱƫÀë O ×îÔ¶£¬ÉèÇеãΪ P £¬¶ÔÓ¦Ô²ÐÄΪO1 £¬ÈçͼËùʾ£¬ÔòÓɼ¸ºÎ¹ØϵµÃ£º  =  =  = 16 cm     

Ïò ¶ËƫתµÄ ¦Á Á£×Ó£¬µ±ÑØ sb ·½ÏòÉäÈëʱ£¬Æ«Àë O ×îÔ¶£¬Éè´ËʱԲÖܹ켣Óë cd ½»ÓÚ Q µã£¬¶ÔÓ¦Ô²ÐÄO2 £¬ÈçͼËùʾ£¬ÔòÓɼ¸ºÎ¹ØϵµÃ£º =  = 16 cm 

¹Ê½ð²­ cd ±» ¦Á Á£×ÓÉäÖÐÇøÓòµÄ³¤¶È L =  =  +  = 32 cm ¡£

£¨3£©Éè´Ó Q µã´©³öµÄ ¦Á Á£×ÓµÄËÙ¶ÈΪ v¡¯£¬Ôڵ糡ÖÐ×öÀàƽÅ×Ô˶¯£¬¹ì¼£ÈçͼËùʾ¡£

ÑØËÙ¶È v¡¯ ·½Ïò×öÔÈËÙÖ±ÏßÔ˶¯£¬Î»ÒÆ s1 =£¨ - R£©sin53o = 16 cm       

Ñس¡Ç¿ E ·½Ïò×öÔȼÓËÙÖ±ÏßÔ˶¯£¬Î»ÒÆ s2 =£¨ - R£©cos53o + R = 32 cm   

ÔòÓÉs1 = v¡¯t        s2 = at2       a = qE/m 

µÃv¡¯ = 8.0¡Á105 m/s     

¹Ê´Ë ¦Á Á£×Ó´Ó½ð²­ÉÏ´©³öʱËðʧµÄ¶¯ÄÜΪ ¡÷Ek = mv2 - mv¡¯ 2 = 3.19¡Á10- 14

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2011?×Ô¹±Ä£Ä⣩ÈçͼËùʾ£¬°ë¾¶ÎªrÔ²ÐÄΪ0µÄÐéÏßËùΧµÄÔ²ÐÎÇøÓòÄÚ´æÔÚ´¹Ö±Ö½ÃæÏòÍâµÄÔÈÇ¿´Å³¡£¬Ôڴų¡ÓÒ²àÓÐÒ»ÊúÖ±·ÅÖõÄƽÐнðÊô°åMºÍN£¬Á½°å¼ä¾àÀëΪÔÚMN°åÖÐÑë¸÷ÓÐÒ»¸öС¿×02¡¢O3£¬O1£¬O2£¬O3ÔÚͬһˮƽֱÏßÉÏ£¬ÓëƽÐнðÊô°åÏà½ÓµÄÊÇÁ½ÌõÊúÖ±·ÅÖüä¾àΪLµÄ×ã¹»³¤µÄ¹â»¬½ðÊôµ¼¹ì£¬µ¼Ìå°ôPQÓëµ¼¹ì½Ó´¥Á¼ºÃ£¬Óë×èֵΪRµÄµç×èÐγɱպϻØ·£®£¨µ¼¹ìÓëµ¼Ìå°ôµÄµç×è²»¼Æ£©£¬¸Ã»Ø·´¦ÔڴŸÐӦǿ¶È´óСΪB£¬·½Ïò´¹Ö±Ö½ÃæÏòÀïµÄÔÈÇ¿´Å³¡ÖУ¬Õû¸ö×°Öô¦ÔÚÕæ¿ÕÊÒÖУ¬ÓÐÒ»ÊøµçºÉÁ¿Îª+q¡¢ÖÊÁ¿ÎªmµÄÁ£×ÓÁ÷£¨ÖØÁ¦²»¼Æ£©£¬ÒÔËÙÂÊV0´ÓÔ²Ðδų¡±ß½çÉϵÄ×îµÍµãEÑذ뾶·½ÏòÉäÈëÔ²Ðδų¡ÇøÓò£¬×îºó´ÓС¿×O3Éä³ö£®ÏÖÊͷŵ¼Ìå°ôPQ£¬ÆäÏ»¬hºó¿ªÊ¼ÔÈËÙÔ˶¯£¬´ËºóÁ£×ÓÇ¡ºÃ²»ÄÜ´ÓO3Éä³ö£¬¶øÊÇ´ÓÔ²Ðδų¡µÄ×î¸ßµãFÉä³ö£®Çó£º
£¨1£©Ô²Ðδų¡µÄ´Å¸ÐӦǿ¶È´óСB¡ä£®
£¨2£©µ¼Ìå°ôµÄÖÊÁ¿M£®
£¨3£©°ôÏÂÂähµÄÕû¸ö¹ý³ÌÖУ¬µç×èÉϲúÉúµÄµçÈÈ£®
£¨4£©Á£×Ó´ÓEµãµ½FµãËùÓõÄʱ¼ä£®
£¨2011?ÎÂÖÝÄ£Ä⣩ÈçͼËùʾ£¬°ë¾¶Îªr¡¢Ô²ÐÄΪO1µÄÐéÏßËùΧµÄÔ²ÐÎÇøÓòÄÚ´æÔÚ´¹Ö±Ö½ÃæÏòÍâµÄÔÈÇ¿´Å³¡£¬Ôڴų¡ÓÒ²àÓÐÒ»ÊúÖ±·ÅÖõÄƽÐнðÊô°åCºÍD£¬Á½°å¼ä¾àÀëΪL£¬ÔÚMN°åÖÐÑë¸÷ÓÐÒ»¸öС¿×O2¡¢O3£®O1¡¢O2¡¢O3ÔÚͬһˮƽֱÏßÉÏ£¬Á½¸ù×ã¹»³¤µÄÖ±½ðÊôµ¼¹ìMN¡¢PQƽÐзÅÖÃÔÚÇã½ÇΪ¦ÈµÄ¾øԵбÃæÉÏ£¬Á½µ¼¹ì¼ä¾àҲΪL£®M¡¢PÁ½µã¼ä½ÓÓÐ×èֵΪRµÄµç×裮һ¸ùÖÊÁ¿ÎªMµÄ¾ùÔÈÖ±½ðÊô¸Ëab·ÅÔÚÁ½µ¼¹ìÉÏ£¬²¢Óëµ¼¹ì´¹Ö±£¬±ÕºÏ»Ø·£¨µ¼¹ìÓëµ¼Ìå°ôµÄµç×è²»¼Æ£©£®ÕûÌ××°Öô¦ÓÚÔÈÇ¿´Å³¡ÖУ¬´Å³¡µÄ´Å¸ÐӦǿ¶ÈΪB£¬´Å³¡·½Ïò´¹Ö±ÓÚбÃæÏòÉÏ£®Õû¸ö×°Öô¦ÔÚÕæ¿ÕÊÒÖУ¬ÓÐÒ»µçºÉÁ¿Îª+q¡¢ÖÊÁ¿ÎªmµÄÁ£×Ó£¨ÖØÁ¦²»¼Æ£©£¬ÒÔËÙÂÊv0´ÓÔ²Ðδų¡±ß½çÉϵÄ×îµÍµãEÑذ뾶·½ÏòÉäÈëÔ²Ðδų¡ÇøÓò£¬×îºó´ÓС¿×O3Éä³ö£®ÏÖÊͷŵ¼Ìå°ôab£¬ÆäÑØ×ÅбÃæÏ»¬hºó¿ªÊ¼ÔÈËÙÔ˶¯£¬´ËʱÈÔÈ»´ÓEµãÑذ뾶·½ÏòÉäÈëÔ²Ðδų¡ÇøÓòµÄÏàͬÁ£×ÓÇ¡ºÃ²»ÄÜ´ÓO3Éä³ö£¬¶ø´ÓÔ²Ðδų¡µÄ×î¸ßµãFÉä³ö£®Çó£º
£¨1£©Ô²Ðδų¡µÄ´Å¸ÐӦǿ¶ÈB¡ä£®
£¨2£©µ¼Ìå°ôµÄÖÊÁ¿M£®
£¨3£©°ôÏÂÂähµÄÕû¸ö¹ý³ÌÖУ¬µ¼Ìå°ôab¿Ë·þ°²ÅàÁ¦×öµÄ¹¦Îª¶àÉÙ£¿

ÈçͼËùʾ£¬°ë¾¶Îª¡¢Ô²ÐÄΪO1µÄÐéÏßËùΧµÄÔ²ÐÎÇøÓòÄÚ´æÔÚ´¹Ö±Ö½ÃæÏòÍâµÄÔÈÇ¿´Å³¡£¬Ôڴų¡ÓÒ²àÓÐÒ»¼áÖ±·ÅÖõÄƽÐнðÊô°åCºÍD£¬Á½°å¼ä¾àÀëΪL£¬ÔÚMN°åÖÐÑë¸÷ÓÐÒ»¸öС¿×O2¡¢O3¡£O1¡¢O2¡¢O3ÔÚͬһˮƽֱÏßÉÏ£¬Á½¸ù×ã¹»³¤µÄÖ±½ðÊôµ¼¹ìMN¡¢PQƽÐзÅÖÃÔÚÇã½ÇΪ¦ÈµÄ¾øԵбÃæÉÏ£¬Á½µ¼¹ì¼ä¾àҲΪL¡£M¡¢PÁ½µã¼ä½ÓÓÐ×èֵΪRµÄµç×è¡£Ò»¸ùÖÊÁ¿ÎªmµÄ¾ùÔÈÖ±½ðÊô¸Ëab·ÅÔÚÁ½µ¼¹ìÉÏ£¬²¢Óëµ¼¹ì´¹Ö±£¬±ÕºÏ»Ø·£¨µ¼¹ìÓëµ¼Ìå°ôµÄµç×è²»¼Æ£©¡£ÕûÌ××°Öô¦ÓÚÔÈÇ¿´Å³¡ÖУ¬´Å³¡µÄ´Å¸ÐӦǿ¶ÈΪB£¬´Å³¡·½Ïò´¹Ö±ÓÚбÃæÏòÉÏ¡£Õû¸ö×°Öô¦ÔÚÕæ¿ÕÊÒÖУ¬ÓÐÒ»µçºÉÁ¿Îª+q¡¢ÖÊÁ¿ÎªmµÄÁ£×Ó£¨ÖØÁ¦²»¼Æ£©£¬ÒÔËÙÂÊv0´ÓÔ²Ðδų¡±ß½çÉϵÄ×îµÍµãÑذ뾶·½ÏòÉäÈëÔ²Ðδų¡ÇøÓò£¬×îºó´ÓС¿×O3Éä³ö¡£ÏÖÊͷŵ¼Ìå°ôab£¬ÆäÑØ×ÅбÃæÏ»¬ºó¿ªÊ¼ÔÈËÙÔ˶¯£¬´ËʱÈÔÈ»´ÓµãÑذ뾶·½ÏòÉäÈëÔ²Ðδų¡ÇøÓòµÄÏàͬÁ£×ÓÇ¡ºÃ²»ÄÜ´ÓO3Éä³ö£¬¶ø´ÓÔ²Ðδų¡µÄ×î¸ßµãFÉä³ö¡£Çó£º

    £¨1£©Ô²Ðδų¡µÄ´Å¸ÐӦǿ¶ÈB/¡£

£¨2£©µ¼Ìå°ôµÄÖÊÁ¿M¡£

    £¨3£©°ôÏÂÂähµÄÕû¸ö¹ý³ÌÖУ¬µ¼Ìå°ôab¿Ë·þ°²ÅàÁ¦×öµÄ¹¦Îª¶àÉÙ£¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø