题目内容
如图所示,A、B两物块置于绕竖直轴匀速转动的水平圆盘上,两物块始终相对圆盘静止,已知两物块的质量mA<mB,运动半径rA >rB,则下列关系一定正确的是
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242314107742765.jpg)
A.角速度ωA =ωB B.线速度vA =vB
C.向心加速度aA >aB D.向心力FA> FB
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408242314107742765.jpg)
A.角速度ωA =ωB B.线速度vA =vB
C.向心加速度aA >aB D.向心力FA> FB
AC
试题分析:AB两物体是同轴转动,所以角速度相等,即ωA =ωB;因为运动半径rA >rB,根据
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824231411273456.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824231412365516.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824231413285503.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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