ÌâÄ¿ÄÚÈÝ

¡¾ÌâÄ¿¡¿ÈçͼËùʾµÄµç·ÖУ¬Á½Ö§Â·µÄµç×èÏàµÈ£¬Á÷¹ýµçÁ÷±íA1µÄµçÁ÷Ç¿¶ÈΪI1£¬Á÷¹ýµçÁ÷±íA2µÄµçÁ÷Ç¿¶ÈΪI2£¬ÔòÔÚ½Óͨ¿ª¹ØSºÍ¶Ï¿ª¿ª¹ØSµÄ˲¼ä£¬¹Û²ìµ½µÄÏÖÏóÊÇ( )

A. ½ÓͨSµÄ˲¼ä£¬I1<I2£»¶Ï¿ªSµÄ˲¼ä£¬I1>I2

B. ½ÓͨSµÄ˲¼ä£¬I1<I2£»¶Ï¿ªSµÄ˲¼ä£¬I1=I2

C. ½ÓͨSµÄ˲¼ä£¬I1=I2£»¶Ï¿ªSµÄ˲¼ä£¬I1<I2

D. ½ÓͨSµÄ˲¼ä£¬I1>I2£»¶Ï¿ªSµÄ˲¼ä£¬I1=I2

¡¾´ð°¸¡¿B

¡¾½âÎö¡¿µ±½Óͨ˲¼ä£¬Í¨¹ýÏßȦLµÄµçÁ÷ÒªÔö¼Ó£¬ÔòÏßȦµÄ²úÉú¸ÐÓ¦µç¶¯ÊÆÈ¥×è°­µçÁ÷Ôö¼Ó£¬´Ó¶øʹµÃµçÁ÷ÂýÂýÔö¼Ó£®¹Ê£¬µ±¶Ï¿ªË²¼ä£¬Í¨¹ýÏßȦLµÄµçÁ÷Òª¼õС£¬ÔòÏßȦµÄ²úÉú¸ÐÓ¦µç¶¯ÊÆÈ¥×è°­µçÁ÷¼õС£¬´Ó¶øʹµÃµçÁ÷ÂýÂý¼õС£®µ«Á½µçÁ÷±íÊÇ´®Áª£¬¹ÊµçÁ÷ÏàµÈ£¬BÕýÈ·£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¡¾ÌâÄ¿¡¿Ä³Í¬Ñ§ÓûÔËÓÃÅ£¶ÙµÚ¶þ¶¨ÂɲâÁ¿»¬¿éµÄÖÊÁ¿M£¬ÆäʵÑé×°ÖÃÈçͼ¼×Ëùʾ£¬Éè¼ÆµÄʵÑé²½ÖèΪ£º

£¨1£©µ÷Õû³¤Ä¾°åÇã½Ç£¬µ±¹³ÂëµÄÖÊÁ¿Îªm0ʱ»¬¿éÇ¡ºÃÑØľ°åÏòÏÂ×öÔÈËÙÔ˶¯£»

£¨2£©±£³Öľ°åÇã½Ç²»±ä£¬³·È¥¹³Âëm0£¬½«»¬¿éÒƽü´òµã¼ÆʱÆ÷£¬È»ºóÊÍ·Å»¬¿é£¬»¬¿éÑØľ°åÏòÏÂ×öÔȼÓËÙÖ±ÏßÔ˶¯£¬²¢´ò³öµã¼£ÇåÎúµÄÖ½´øÈçͼÒÒËùʾ(´òµã¼ÆʱÆ÷µÄ¹¤×÷ƵÂÊΪ50Hz)£®

Çë»Ø´ðÏÂÁÐÎÊÌ⣺

¢Ù´òµã¼ÆʱÆ÷ÔÚ´òÏÂDµãʱ»¬¿éµÄËÙ¶ÈvD=__________m/s£»(½á¹û±£Áô3λÓÐЧÊý×Ö)

¢Ú»¬¿é×öÔȼÓËÙÖ±ÏßÔ˶¯µÄ¼ÓËÙ¶Èa=_____m/s2£»(½á¹û±£Áô3λÓÐЧÊý×Ö)

¢Û»¬¿éÖÊÁ¿M=___________(ÓÃ×Öĸa¡¢m0ºÍµ±µØÖØÁ¦¼ÓËÙ¶Èg±íʾ)£®

£¨3£©±£³Öľ°åÇã½Ç²»±ä£¬¹ÒÉÏÖÊÁ¿Îªm(¾ùСÓÚm0)µÄ¹³Â룬»¬¿éÑØľ°åÏòÏÂÔȼÓËÙÔ˶¯£¬²â³ö»¬¿éµÄ¼ÓËٶȣ»¶à´Î¸Ä±ä¹³ÂëµÄÖÊÁ¿£¬·Ö±ðÇó³öÏàÓ¦µÄ¼ÓËٶȣ®

£¨4£©ÈôÉþµÄÀ­Á¦ÓëËù¹Ò¹³ÂëµÄÖØÁ¦´óСÏàµÈ£¬×÷³öa¡ªmgͼÏóÈçͼ±ûËùʾ£¬ÔòÓÉͼ±û¿ÉÇóµÃ»¬¿éµÄÖÊÁ¿M=______kg£®(È¡g=10m/s2£¬½á¹û±£Áô3λÓÐЧÊý×Ö)

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø