题目内容
甲、乙两物体在光滑水平面上沿同一直线相向运动,甲、乙物体的速度大小分别为3m/s和1 m/s;碰撞后甲、乙两物体都反向运动,速度大小均为2m/s。则甲、乙两物体质量之比为:( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241647145635276.jpg)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241647145635276.jpg)
A.2∶3 | B.2∶5 | C.3∶5 | D.5∶3 |
C
试题分析:碰撞过程中动量守恒,根据动量守恒定律即可求解.
由动量守恒定律得:P初=P末,根据
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824164714704919.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824164715094944.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824164715499683.png)
点评:本题是动量守恒定律的简单应用,难度不大,属于基础题.
![](http://thumb2018.1010pic.com/images/loading.gif)
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