ÌâÄ¿ÄÚÈÝ

7£®ÈçͼËùʾ£¬Ò»¡°V¡±ÐιìµÀPOQÓÉбÃæÓëˮƽÃ棨×ã¹»³¤£©ÔÚO´¦Æ½»¬Á¬½Ó¶ø³É£®ÔÚбÃæQOÉÏ£¬½«²»Í¬¸ß¶È´¦µÄA¡¢BÁ½Îï¿é£¨¾ùÊÓΪÖʵ㣩ͬʱÓɾ²Ö¹¿ªÊ¼ÊÍ·Å£¬ËüÃÇÒÔ¹²Í¬µÄ¼ÓËÙ¶Èa1=5m/s2ÑØбÃæ¹ìµÀÏ»¬£¬µ±ËüÃÇͨ¹ýOµã½øÈëˮƽ¹ìµÀºó£¬½«»á×öÔȼõËÙÖ±ÏßÔ˶¯£¬ÇÒ¼ÓËٶȴóС¾ùΪa2=1m/s2£®ÒÑÖªA¡¢BÁ½Îï¿é³õʼλÖþàбÃæµ×¶ËOµÄ¾àÀë·Ö±ðΪLA=6.4m£¬LB=0.9m£¬ÇÒÁ½Îï¿éͨ¹ýO´¦¹ý³ÌµÄËٶȴóС²»±ä£¬Çó£º
£¨1£©Îï¿éA»¬µ½OµãʱÓëÎï¿éB¼äµÄ¾àÀëL£»
£¨2£©Îï¿éA´Ó¿ªÊ¼ÊÍ·ÅÖÁ×·ÉÏÎï¿éBËùÓõÄʱ¼ät£®

·ÖÎö £¨1£©ÀûÓÃλÒÆʱ¼ä¹«Ê½ÇóµÃABÔÚбÃæÉÏÔ˶¯µÄʱ¼ä¼°µ½´ïOµãµÄËٶȣ¬ÀûÓÃˮƽÃæÉϵÄʱ¼äºÍÔ˶¯Ñ§¹«Ê½¼´¿ÉÇóµÃ
£¨2£©ÏÈÅжϳöA×·ÉÏBʱ£¬BÊÇ·ñ´¦ÓÚ¾²Ö¹×´Ì¬£¬È»ºóÔÙÀûÓÃÔ˶¯Ñ§¹«Ê½ÇóµÃʱ¼ä

½â´ð ½â£º»¬¿éAÏ»¬µ½OµãµÄʱ¼äΪtA£¬Ôò${L}_{A}=\frac{1}{2}{{a}_{1}t}_{A}^{2}$
${t}_{A}=\sqrt{\frac{2{L}_{A}}{{a}_{1}}}=\sqrt{\frac{2¡Á6.4}{5}}s=1.6s$
»¬¿éAÏ»¬µ½OµãµÄʱ¼äΪtB£¬Ôò${L}_{B}=\frac{1}{2}{at}_{B}^{2}$
½âµÃ${t}_{B}=\sqrt{\frac{2{L}_{B}}{{a}_{1}}}=\sqrt{\frac{2¡Á0.9}{5}}s=0.6s$
Bµ½´ïOµãµÄËÙ¶ÈvB=a1tB=3m/s
µ±Aµ½´ïOµãºó£¬BÔÚˮƽÃæÉÏ»¬ÐеÄʱ¼ä¡÷t=tA-tB=1s
»¬ÐеľàÀë$x={v}_{B}¡÷t-\frac{1}{2}{a}_{2}£¨¡÷t£©^{2}$=$3¡Á1-\frac{1}{2}¡Á1¡Á{1}^{2}m=2.5m$
£¨2£©AÏ»¬µ½OµãËÙ¶ÈvA=a1tA=8m/s
B¼õËÙµ½ÁãËùÐèʱ¼ä$t=\frac{{v}_{B}}{{a}_{2}}=\frac{3}{1}s=3s$
3sÄÚBͨ¹ýµÄλÒÆ$x¡ä=\frac{{v}_{B}^{2}}{2{a}_{2}}=\frac{9}{2¡Á1}m=4.5m$
´ËʱAÔÚˮƽÃæÉÏÔ˶¯2s£¬Í¨¹ýµÄλÒÆ$x¡å={v}_{A}t-\frac{1}{2}{a}_{2}{t}^{2}=14m$£¬¹ÊÔÚB¾²Ö¹Ç°A×·ÉÏB
¹Ê${v}_{A}{t}_{Ë®}-\frac{1}{2}{{a}_{2}t}_{Ë®}^{2}={v}_{B}£¨¡÷t+{t}_{Ë®}£©-\frac{1}{2}$${a}_{2}£¨¡÷t+{t}_{Ë®}£©^{2}$
½âµÃ$t=\frac{5}{12}s$
¹ÊÎï¿éA´Ó¿ªÊ¼ÊÍ·ÅÖÁ×·ÉÏÎï¿éBËùÓõÄʱ¼äΪ£ºt×Ü=tA+t=2.02s
´ð£º£¨1£©Îï¿éA»¬µ½OµãʱÓëÎï¿éB¼äµÄ¾àÀëLΪ2.5m£»
£¨2£©Îï¿éA´Ó¿ªÊ¼ÊÍ·ÅÖÁ×·ÉÏÎï¿éBËùÓõÄʱ¼äΪ2.02s

µãÆÀ ±¾Ì⿼²é×·»÷ÎÊÌ⣬ץסÔÚˮƽÃæÉÏAÔÚ×·ÉÏBʱ£¬A±ÈBÉÙÔ˶¯1s£¬È»ºóÀûÓúÃÔ˶¯Ñ§¹«Ê½£¬¹Ø¼üÊÇÅжÏA×·ÉÏBʱ£¬BÊÇ·ñ¾²Ö¹£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
19£®¼×ÒÒÁ½Î»Í¬Ñ§ÀûÓô©¹ý´òµã¼ÆʱÆ÷µÄÖ½´øÀ´¼Ç¼С³µµÄÔ˶¯£¬´òµã¼ÆʱÆ÷ËùÓõçÔ´µÄƵÂÊΪ50Hz£®
£¨1£©ÓйزÙ×÷ºÍ²âÁ¿µÄ˵·¨ÖÐÕýÈ·µÄÊÇBC
A£®ÏÈÊÍ·ÅС³µ£¬ÔÙ½ÓͨµçÔ´£¬µ±Ð¡³µµ½´ï»¬ÂÖÇ°¼°Ê±ÓÃÊÖ°´×¡Ëüºó¹Ø±ÕµçÔ´
B£®¿ªÊ¼ÊÍ·ÅС³µÇ°£¬Ó¦Ê¹Ð¡³µ¿¿½ü´òµã¼ÆʱÆ÷
C£®²âÁ¿Ê±Ó¦ÉáÈ¥Ö½´øÉϵÄÃܼ¯µã£¬È»ºóÑ¡È¡¼ÆÊýµã
D£®±ØÐëÿ5¸ö´òÓ¡µãÉèÒ»¸ö¼ÆÊýµã
£¨2£©ÊµÑéºó£¬¼×ͬѧѡÔñÁËÒ»Ìõ½ÏΪÀíÏëµÄÖ½´ø£¬²âÁ¿Êý¾Ýºó£¬Í¨¹ý¼ÆËãµÃµ½ÁËС³µÔ˶¯¹ý³ÌÖи÷¼Æʱʱ¿ÌµÄËÙ¶ÈÈç±í¸ñËùʾ£®
λÖñàºÅ00.10.20.30.4
ʱ¼ät/s00.10.20.30.4
ËÙ¶Èv/m•s-10.420.670.921.161.42
·ÖÎö±íÖÐÊý¾Ý£¬ÔÚÎó²îÔÊÐíµÄ·¶Î§ÄÚ£¬Ð¡³µ×öÔȼÓËÙÖ±ÏßÔ˶¯£»ÓÉÓÚ´Ë´ÎʵÑéµÄԭʼֽ´øûÓб£´æ£¬¸ÃͬѧÏë¹ÀËãС³µ´ÓλÖÃ0µ½Î»ÖÃ5µÄλÒÆ£¬Æä¹À¼ÆËã·½·¨ÈçÏ£ºx=£¨0.42¡Á0.1+0.67¡Á0.1+0.92¡Á0.1+1.16¡Á0.1+1.42¡Á0.1£©m£¬ÄÇô£¬¸ÃͬѧµÃµ½µÄλÒÆСÓÚ£¨Ñ¡Ìî¡°´óÓÚ¡±¡¢¡°µÈÓÚ¡±»ò¡°Ð¡ÓÚ¡±£©Êµ¼ÊλÒÆ£®
£¨3£©Ä³Í¬Ñ§ÀûÓôòµã¼ÆʱÆ÷Ëù¼Ç¼µÄÖ½´øÀ´Ñо¿Ð¡³µ×ö   ÔȱäËÙÖ±ÏßÔ˶¯µÄÇé¿ö£¬ÊµÑéÖлñµÃÒ»ÌõÖ½´ø£¬Èçͼ£¬ÆäÖÐÁ½ÏàÁÚ¼ÆÊýµã¼äÓÐÁ½¸öµãδ»­³ö£®ÒÑÖªËùÓõçÔ´µÄƵÂÊΪ50Hz£¬Ôò´òBµãʱС³µÔ˶¯µÄËٶȴóСvB=1.32m/s£¬Ð¡³µÔ˶¯µÄ¼ÓËٶȴóСa=8.33m/s2£®£¨¼ÆËã½á¹û±£Áô3λÓÐЧÊý×Ö£©

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø