ÌâÄ¿ÄÚÈÝ

7£®ÔڲⶨijÐÂÐ͵ç³ØµÄµç¶¯ÊƺÍÄÚ×èµÄʵÑéÖУ¬ËùÌṩµÄÆ÷²ÄÓУº
´ý²âµç³Ø£¨µç¶¯ÊÆÔ¼6V£©
µçÁ÷±íG£¨Á¿³Ì6.0mA£¬ÄÚ×èr1=100¦¸£©
µçÁ÷±íA£¨Á¿³Ì0.6A£¬ÄÚ×èr2=5.0¦¸£©
¶¨Öµµç×èR1=100¦¸
¶¨Öµµç×èR2=900¦¸
»¬¶¯±ä×èÆ÷R¡ä£¨0-50¦¸£©
¿ª¹Ø¡¢µ¼ÏßÈô¸É
£¨1£©ÎªÁ˾«È·²â³ö¸Ãµç³ØµÄµç¶¯ÊƺÍÄÚ×裬²ÉÓÃͼ¼×ËùʾʵÑéµç·ͼ£¬ÆäÖж¨Öµµç×èӦѡÓÃR2£¨Ñ¡ÌîR1»òR2£©£®
£¨2£©Ä³Í¬Ñ§ÔÚʵÑéÖвâ³öµçÁ÷±íAºÍµçÁ÷±íGµÄʾÊýIºÍIg£¬¸ù¾Ý¼Ç¼Êý¾Ý×÷³öIg-IͼÏóÈçͼÒÒËùʾ£¨Í¼ÏóµÄбÂÊÓÃk±íʾ£©£®¸ù¾ÝͼÏó¿ÉÇóµÃ£¬±»²âµç³Øµç¶¯ÊÆֵΪ5.8V£»ÄÚ×èµÄ±í´ïʽr=-k£¨r1+R2£©-r2£¬ÆäֵΪ2£®

·ÖÎö ±íÍ·¼°¶¨Öµµç×è´®Áª¿É³äµ±µçѹ±íʹÓã¬ÔòÓɱպϵç·ŷķ¶¨Âɿɵóö±í´ïʽ£¬ÓÉͼÏó½áºÏ±í´ïʽ¿ÉµÃ³öµç¶¯ÊƺÍÄÚµç×裻

½â´ð ½â£º£¨1£©ÓÉÓÚÌâÄ¿ÖÐûÓеçѹ±í£¬ËùÒÔÓõçÁ÷¼ÆºÍ¶¨Öµµç×è´®Áª£¬¸Ä×°³Éµçѹ±í£¬´ý²âµç³ØµÄµç¶¯ÊÆԼΪ6V£¬ËùÒÔ
Ó¦´®ÁªµÄµç×èR=$\frac{6}{0.006}-100$=900¦¸£¬¹ÊÑ¡R2£»
£¨2£©±íÍ·µÄʾÊýÓ붨ֵµç×è×èÖµµÄ³Ë»ý¿É×÷Ϊ·¶Ëµçѹ´¦Àí£¬ÔòÓɱպϵç·ŷķ¶¨ÂÉ¿ÉÖª£º
Ig£¨R2+r1£©=E-I£¨r+r2£©
½âµÃ£ºIg=$-\frac{r{+r}_{2}}{{R}_{2}{+r}_{1}}$I+$\frac{E}{{R}_{2}{+r}_{1}}$
ËùÒÔb=$\frac{E}{{R}_{2}{+r}_{1}}$
½âµÃ£ºE=b£¨r1+R2£©£¬ÓÉͼÏóµÃ£ºE=5.8V
k=$-\frac{r{+r}_{2}}{{R}_{2}{+r}_{1}}$
½âµÃ£ºr=-k£¨r1+R2£©-r2
Ôòr=2¦¸
¹Ê´ð°¸Îª£º¢Ù¡¢R2
£¨2£©ÈçͼËùʾ5.8V£» r=-k£¨r1+R2£©-r2£»2¦¸

µãÆÀ ±¾ÌâΪ²âÁ¿µçÔ´µÄµç¶¯ÊƺÍÄÚµç×èµÄʵÑéµÄ±äÐΣ¬×¢ÒâÓÉÓÚûÓеçѹ±í£¬±¾ÊµÑéÖвÉÓøÄ×°µÄ·½Ê½½«±íÍ·¸ÄװΪµçѹ±í£¬ÔÙ¸ù¾ÝԭʵÑéµÄÑо¿·½·¨½øÐзÖÎöÑо¿£®

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø