题目内容
设向量

(1)将y表示为x的函数y=f(x)
(2)若tanA,tanB是方程f(x)+4=0的两个实根,A,B是锐角三角形ABC的两个内角,求证:m
(3)对任意实数


(1)将y表示为x的函数y=f(x)
(2)若tanA,tanB是方程f(x)+4=0的两个实根,A,B是锐角三角形ABC的两个内角,求证:m

(3)对任意实数

(1)解:y="f(x)=" 
(2)证明:
由题意可知
]
即
∴
∵tanC="-tan(A+B)=" -
>0
∴m>-1或m<-3
综上,
(3)令t=2+cos
,则
由题意可知
即
∵
∴

(2)证明:

由题意可知

即

∴

∵tanC="-tan(A+B)=" -

∴m>-1或m<-3
综上,

(3)令t=2+cos


由题意可知

即

∵

∴

略

练习册系列答案
相关题目