题目内容
计算:
(n-
)= .
lim |
n→∞ |
n2+2 |
n+1000 |
分析:先化简,然后由极限运算性质可求.
解答:解:∵n-
=
=1000-
,
∴
(n-
)=
(1000-
)=1000,
故答案为:1000.
n2+2 |
n+1000 |
1000n-2 |
n+1000 |
1000002 |
n+1000 |
∴
lim |
n→∞ |
n2+2 |
n+1000 |
lim |
n→∞ |
1000002 |
n+1000 |
故答案为:1000.
点评:本题考查数列的极限求解,属中档题,正确理解数列极限的运算性质是解题关键.
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