题目内容
如图,已知多面体
中,
平面
,
平面
,
,
,
为
的中点
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(1)求证:
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;
(2)求多面体
的体积.
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(1)求证:
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(2)求多面体

(1)见解析 (2)
.
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(1)本小题可以取CD的中点O,连接OF,AO,证明
即可.
(2)因为AC=CD,取AD中点H,连CH,因为
平面
,知CH
面ABED,
所以四棱锥C-ABED的高确定
(1)取CD的中点O,连接AO、OF,则OF//DE, 2分
AC=AD,
AO
CD
DE
平面ACD
DE
CD
OF
CD,又
CD
平面AOF
AF
平面AOF
AF
CD. 8分
(2) 取AD中点H,连CH 知CH
面ABED CH=
10分
. 12分
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(2)因为AC=CD,取AD中点H,连CH,因为
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所以四棱锥C-ABED的高确定
(1)取CD的中点O,连接AO、OF,则OF//DE, 2分
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(2) 取AD中点H,连CH 知CH
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