题目内容
已知a、b不共线,

A.k+l=0 B.k-l=0 C.kl+1=0 D.kl-1=0
D
解析:若与
共线,则
=λ
,
a+kb=λ(la+b)即a+kb=lλ(a+),
k=,∴kl-1=0.

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题目内容
已知a、b不共线,A.k+l=0 B.k-l=0 C.kl+1=0 D.kl-1=0
D
解析:若与
共线,则
=λ
,
a+kb=λ(la+b)即a+kb=lλ(a+),
k=,∴kl-1=0.