题目内容
已知曲线C1的参数方程为
(t为参数),以坐标原点为极点,x轴的正半轴为极轴建立极坐标系,曲线C2的极坐标方程为
.
(1)把C1的参数方程化为极坐标方程;
(2)求C1与C2交点的极坐标(ρ≥0,0≤θ<2π).


(1)把C1的参数方程化为极坐标方程;
(2)求C1与C2交点的极坐标(ρ≥0,0≤θ<2π).
(1)
(2)(
,
),(2,
)
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(1)将
消去参数t,化为普通方程
,
即C1:
.
将
代入
得
.
所以C1的极坐标方程为
.
(2)C2的普通方程为
.
由
解得
或
所以C1与C2交点的极坐标分别为(
,
),(2,
)
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
即C1:

将
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
所以C1的极坐标方程为

(2)C2的普通方程为

由
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解得
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
所以C1与C2交点的极坐标分别为(

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