题目内容
(本小题13分)已知椭圆
,椭圆
以
的长轴为短轴,且与
有相同的离心率.
(1)求椭圆
的方程;
(2)设O为坐标原点,点A,B分别在椭圆
和
上,
,求直线
的方程.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306441771.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306456372.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306581339.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306581339.png)
(1)求椭圆
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306456372.png)
(2)设O为坐标原点,点A,B分别在椭圆
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306581339.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306456372.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306675608.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306690396.png)
(1)
(2)
或![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306737407.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306706750.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306721402.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306737407.png)
试题分析:(1)由已知可设椭圆
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306456372.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306768993.png)
其离心率为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306799453.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306815767.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306846371.png)
故椭圆的方程为
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306706750.png)
(2)解法一
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306862423.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306877744.png)
由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306675608.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306909497.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306940300.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306955309.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306971310.png)
因此可以设直线
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306690396.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306987473.png)
将
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306987473.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307033636.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307049700.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307049692.png)
将
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306987473.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307080733.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307096736.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307111761.png)
由
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306675608.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307143576.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307174787.png)
解得
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005307189381.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306690396.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306721402.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824005306737407.png)
点评:第二问由已知中的向量可知只需求解出A,B两点坐标代入即可得到关于所求直线斜率k的直线,因此设AB直线,联立方程解出方程组
![](http://thumb.zyjl.cn/images/loading.gif)
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