题目内容
18.若集合M={x|x2+x-2≤0},N={-2,-1,1,2},则M∩N等于( )A. | {-1,1,2} | B. | {1} | C. | {-1,1} | D. | {-2,-1,1} |
分析 求出集合M,即可求解交集.
解答 解:集合M={x|x2+x-2≤0}={x|-2≤x≤1},N={-2,-1,1,2},则M∩N={-2,-1,1}.
故选:D.
点评 本题考查交集的求法,基本知识的考查.
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