题目内容
(本小题满分10分)
(Ⅰ)解关于x的不等式:
;
(Ⅱ)若关于
的不等式
有解,求实数
的取值范围.
(Ⅰ)解关于x的不等式:
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(Ⅱ)若关于
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解::(Ⅰ) ①当
时,原不等式可化为:
;即
;
又∵
,∴
; ………………………………………………2分
②当
时, 原不等式可化为:
3,显然成立;
∴
;
………………………………………………4分
③当
时,原不等式可化为:
,即
2;
又∵
,∴
………………………………………………6分
综上所述,原不等式的解集为
. ………………………………………7分
(Ⅱ)由绝对值的几何意义可知,
表示数轴上坐标为
的点到原点与到坐标为1的点的距离之和,则
的最小值为1.要使不等式
有解,则
1.-……10分
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又∵
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②当
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∴
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③当
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又∵
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综上所述,原不等式的解集为

(Ⅱ)由绝对值的几何意义可知,
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略
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