题目内容

在数列{an}中,a1=,点(anan+1)(n∈N*)在直线y=x+
(Ⅰ)求数列{an}的通项公式;
(Ⅱ)记bn=,求数列{bn}的前n项和Tn
(Ⅰ)由已知得,即.············ 1分
∴ 数列是以为首项,以为公差的等差数列.··········· 2分
∵ ···························· 3分
∴ ).····················· 6分
(Ⅱ)由(Ⅰ)得,················· 7分
∴ .  ·························· 9分
∴ 
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