题目内容
如图,在四棱锥P-ABCD中,PA⊥平面ABCD,底面ABCD是菱形,点O是对角线AC与BD的交点,M是PD的中点,AB=2,∠BAD=60°.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240348242444391.jpg)
(1)求证:OM∥平面PAB;
(2)求证:平面PBD⊥平面PAC;
(3)当四棱锥P-ABCD的体积等于
时,求PB的长.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240348242444391.jpg)
(1)求证:OM∥平面PAB;
(2)求证:平面PBD⊥平面PAC;
(3)当四棱锥P-ABCD的体积等于
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824260344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824275368.png)
(1)证明∵在△PBD中,O,M分别是BD,PD的中点,∴OM是△PBD的中位线,∴OM∥PB.
∵OM?平面PAB,PB?平面PAB,∴OM∥平面PAB.
(2)证明∵底面ABCD是菱形,∴BD⊥AC.∵PA⊥平面ABCD,BD?平面ABCD,∴PA⊥BD.又AC?平面PAC,PA?平面PAC,AC∩PA=A,∴BD⊥平面PAC.∵BD?平面PBD,∴平面PBD⊥平面PAC.
(3)解∵底面ABCD是菱形,AB=2,∠BAD=60°,
∴S菱形ABCD=2×
×AB×AD×sin 60°=2×2×
=2
.
∵四棱锥P-ABCD的高为PA,∴
×2
×PA=
,解得PA=
.又∵PA⊥平面ABCD,AB?平面ABCD,∴PA⊥AB.在Rt△PAB中,PB=
=
=
.
∵OM?平面PAB,PB?平面PAB,∴OM∥平面PAB.
(2)证明∵底面ABCD是菱形,∴BD⊥AC.∵PA⊥平面ABCD,BD?平面ABCD,∴PA⊥BD.又AC?平面PAC,PA?平面PAC,AC∩PA=A,∴BD⊥平面PAC.∵BD?平面PBD,∴平面PBD⊥平面PAC.
(3)解∵底面ABCD是菱形,AB=2,∠BAD=60°,
∴S菱形ABCD=2×
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824494338.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824525453.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824260344.png)
∵四棱锥P-ABCD的高为PA,∴
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824572327.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824260344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824260344.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824603388.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824619647.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824634717.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034824275368.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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