题目内容
已知锐角△ABC中内角A,B,C的对边分别为a,b,c,且c=6,向量
=(2sinC,-
),
=(cos2C,2cos2
-1),且
∥
.
(1)求C的大小;
(2)若sinA=
,求sin(
-B)的值.
s |
3 |
t |
C |
2 |
s |
t |
(1)求C的大小;
(2)若sinA=
1 |
3 |
π |
3 |
(1)∵
∥
,∴2sinC(2cos2
-1)=-
cos2C,
∴sin2C=-
cos2C,即tan2C=-
,
又∵C为锐角,∴2C∈(0,π),∴2C=
,∴C=
;
(2)∵C=
,∴A=
-B,
∴sin(
-B)=sin[(
-B)-
]=sin(A-
),
又sinA=
,且A为锐角,∴cosA=
,
∴sin(
-B)=sin(A-
)=sinAcos
-cosAsin
=
;
s |
t |
C |
2 |
3 |
∴sin2C=-
3 |
3 |
又∵C为锐角,∴2C∈(0,π),∴2C=
2π |
3 |
π |
3 |
(2)∵C=
π |
3 |
2π |
3 |
∴sin(
π |
3 |
2π |
3 |
π |
3 |
π |
3 |
又sinA=
1 |
3 |
2
| ||
3 |
∴sin(
π |
3 |
π |
3 |
π |
3 |
π |
3 |
1-2
| ||
6 |
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