题目内容
已知△OAB中,点C是点B关于点A的对称点,点D是线段OB的一个靠近B的三等分点,设
=
,
=
.
(1)用向量
与
表示向量
,
;
(2)若
=
,求证:C、D、E三点共线.

AB |
a |
AO |
b |
(1)用向量
a |
b |
OC |
CD |
(2)若
OE |
4 |
5 |
OA |

(1)∵
=
,
=
∴
=
+
=-
-
=
+
=
+
=
+
(
+
)=2
+
(-
+
)=
+
(2)∵
=
-
=
(-
)+
+
=
+
=
∴
与
又∵
与
有公共点C,
∴C、D、E三点共线
AB |
a |
AO |
b |
∴
OC |
OA |
AC |
a |
b |
CD |
CB |
BD |
CB |
1 |
3 |
BO |
CB |
1 |
3 |
BA |
AO |
a |
1 |
3 |
a |
b |
5 |
3 |
a |
1 |
3 |
b |
(2)∵
CE |
OE |
OC |
4 |
5 |
b |
a |
b |
a |
1 |
5 |
b |
3 |
5 |
CD |
∴
CE |
CD |
又∵
CE |
CD |
∴C、D、E三点共线

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