题目内容
在平面直角坐标系xOy中,点A(5,0),对于某个正实数k,存在函数f(x)=ax2
(a>0),使得
(λ为常数),这里点P、Q的坐标分别为
P(1,f(1)),Q(k,f(k)),则k的取值范围为( )
(a>0),使得
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/201408232008202611360.png)
P(1,f(1)),Q(k,f(k)),则k的取值范围为( )
A.(2,+∞) | B.(3,+∞) | C.[4,+∞) | D.[8,+∞) |
A
解:由题设知,点P(1,a),Q(k,ak2),A(5,0),
∴向量
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820277380.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820292395.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820308393.png)
∴
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820323513.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820339523.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820370632.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820386688.png)
∵
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/201408232008202611360.png)
∴1=λ(1+
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820370632.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820823781.png)
两式相除得,k-1=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820885566.png)
k-2=a2k>0
∴k(1-a2)=2,且k>2.
∴k=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820885513.png)
∴k=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140823/20140823200820885513.png)
故选A.
![](http://thumb.zyjl.cn/images/loading.gif)
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