题目内容
若



【答案】分析:由题设条件知椭圆
的焦点即为C,D两点,根据椭圆的定义得出|MC|+|MD|为定值,从而利用基本不等式得到
的最小值.
解答:解:由题设条件知焦点在x轴上,
故椭圆方程椭圆
由c=
=
,
易知C,D两点是椭圆
的焦点,
所以,|MC|+|MD|=2a=4,
从而|MC|•|MD|≤(
)2=22=4,
当且仅当|MC|=|MD|取等号,
即点M的坐标为(0,±1)时上式取等号,
∴
=
≥
,
则
的最小值为 1.
故答案为:1.
点评:本题考查圆锥曲线的综合应用,基本不等式及两点间的距离公式.解题时要认真审题,仔细求解.


解答:解:由题设条件知焦点在x轴上,
故椭圆方程椭圆

由c=


易知C,D两点是椭圆

所以,|MC|+|MD|=2a=4,
从而|MC|•|MD|≤(

当且仅当|MC|=|MD|取等号,
即点M的坐标为(0,±1)时上式取等号,
∴



则

故答案为:1.
点评:本题考查圆锥曲线的综合应用,基本不等式及两点间的距离公式.解题时要认真审题,仔细求解.

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