题目内容

已知在△OAB(O为原点)中,
OA
=(2cosa,2sina),
OB
=(5cosb,5sinb),若
OA
OB
=-5,则S△AOB的值为______.
OA
=(2cosa,2sina),
OB
=(5cosb,5sinb),
|
OA
|
=2,|
OB
|
=5,
又∵
OA
OB
=-5,
可得:cos∠O=-
1
2

则sin∠O=
1-cos2∠O
=
3
2

∴S△AOB=
1
2
|
OA
|
|
OB
|
3
2
=
5
3
2

故答案为:
5
3
2
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