题目内容
设椭圆![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_ST/0.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_ST/1.png)
【答案】分析:应用椭圆的第二定义,转化
为P到右准线的距离,然后求出
的最小值就是A到右准线的距离.
解答:
解:
,a=5,b=4,c=3,e=
,椭圆的右准线x=
,
如图,
设P到准线距离=d,
,d=
.
所以
=|PA|+d≥
-1=
.
故答案为:
.
点评:本题是中档题,考查椭圆的第二定义,转化思想的应用,考查计算能力.
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/0.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/1.png)
解答:
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/images2.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/2.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/3.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/4.png)
如图,
设P到准线距离=d,
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/5.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/6.png)
所以
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/7.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/8.png)
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/9.png)
故答案为:
![](http://thumb.zyjl.cn/pic6/res/gzsx/web/STSource/20131024183410532550969/SYS201310241834105325509013_DA/10.png)
点评:本题是中档题,考查椭圆的第二定义,转化思想的应用,考查计算能力.
![](http://thumb.zyjl.cn/images/loading.gif)
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